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4vir4ik [10]
3 years ago
11

A ball is dropped from a cliff that is 135 m high.

Mathematics
1 answer:
Anna [14]3 years ago
4 0

Answer:

113 feet

Step-by-step explanation:

I will assume you meant h = -4.9t^2 + 135; "t2" is incorrect.

To answer this question, to find the height of the ball after 2.1 seconds, substitute 2.1 for t in the above equation:

h(2.1) = -4.9(2.1)^2 + 135.  This becomes -21.6 + 135, or 113.4.

The closest result to the height of the ball after 2.1 seconds is 113 feet.

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If 3/4y=6-1/3c then what is the value of 2c+9/2y
rosijanka [135]

Answer:

36

Step-by-step explanation:

3/4y=6-1/3c

3/4y+1/3c=6

multiplied 6 into equation to get 2c

9/2y+2c=36

so 2c+9/2y=36

4 0
3 years ago
Sarah made 12 more free throws than Connie. How many free throws did Connie make if Sarah made 72?
Annette [7]
Connie made 60 throws and Sarah made 72.
4 0
4 years ago
Read 2 more answers
Which congruency statements could be correct for the figures? Check all that apply. MNOP ≅ STUV MNPO ≅ TSVU NPOM ≅ VUTS OPNM ≅ T
jeka94

Answer:

NPOM ≅ VUTS

OPNM ≅ TUVS

Step-by-step explanation: Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent,  where, OM is congruent or equal to TS and in quadrilaterals NPOM and  VUTS-

since, the condition and, side UV=side  OM   follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

7 0
3 years ago
Read 2 more answers
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
25 POINTS!
lubasha [3.4K]
To solve this you'll plug in the ordered pairs and if the answer is equal then it is the answer.

A: 2 = 3(0) - 2
     2 = 0 - 2 
     2 ≠ -2

B: 1 = 3(1) - 2
     1 = 3 - 2
      1 = 1

C: 1 = 3(-3) - 2
      1 = -9 - 2
       1 ≠ -11

D: 0 = 3(2) - 2
     0 = 6 - 2
     0 ≠ 4

So the answer choice B is the solution to the given equation.

Hope this helps :)
8 0
3 years ago
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