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3 years ago

This is literary super easy, all I need is coordinates.

Mathematics

1 answer:

Juliette [100K]3 years ago

3 0

Answer:

m (2,6), L (3, -6), J (-6, -9), K (-1, -9)

Step-by-step explanation:

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HELP ME!,!,,,! I’ve been waiting for 30 minutes

Furkat [3]

Answer:

5/9=1/2

12/13=1

2/13=0

Step-by-step explanation:

These are just based on what I think and also

5/9=0.55... so closer to 0.5 which =1/2

12/13 is just really close to 13/13

2/13 is really close to 0/13 rather than 6.5/13, which is 1/2

5 0

2 years ago

Cos(0.5)+cos(0.5+2(3.14159265))+cos(0.5+4(3.14159265))

aleksandr82 [10.1K]

Answer:

2.63274768567

Step-by-step explanation:

First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.

2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).

So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567

I hope this helps! :)

7 0

3 years ago

Can someone please help me? I can't find the h(x) for 0. I also need help with the last question. Please I need it very soon.

Solnce55 [7]

9514 1404 393

Answer:

see attachments for a table and graph

Step-by-step explanation:

I find it convenient to use a graphing calculator or spreadsheet to do repetitive computations reliably.

Your specific question asks for h(0):

h(0) = -|0 +2| +1 = -2 +1

h(0) = -1

You may want to check your other table values.

8 0

2 years ago

Can someone please help me and explain

Fiesta28 [93]

Answer:

0.23

Step-by-step explanation:

3 0

3 years ago

CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte

rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

$\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt$

By definition of absolute value,

$|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)$

Over this particular integration interval,

• sin(t ) ≥ 0 for 1 ≤ t < π, and

• sin(t ) < 0 for π < t ≤ 5

so you end up splitting the integral at t = π as

$\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt$

Now compute the distance:

$\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5$

$\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))$

$\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82$

making B the correct answer.

7 0

2 years ago