Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
78 rounded to the nearest tenth is 80
Answer:
3135
Step-by-step explanation:
Givens
a1 = 6
Use t4 - t3 to get d
t4 = 27
t3 = 20
Step One
Find a1 and d
a1 = 6
d = t4 - t3
d = 27 - 20
d = 7
Step Two
Find the 30th Term
tn= a1 + (n -1 )*d
t30 = 6 + (30 - 1) * 7
t30 = 6 + 29*7
t30 = 6 + 203
t30 = 209
Step Three
Find the sum using Sum = (a + t30)*n/2
n = 30 given
a1 = 6 given
t30 = 209 calculated from step 2
Sum = (a1 + t30)*n/2 Substitute
Sum = (6+ 209)*30/2 Combine like terms and divide by 2
sum = 215 * 15 Multiply
Sum = 3135 Answer
Area of a rectangle = b*h... so 6ft*5ft = 30 ft^2
