Tgerebare many properties of logarithms that are useful for simplifying and solving such as e^ln(x)=x, alog(x)=log(x^a), addition and subtraction rules (log(x)-log(x^2)=log(x/x^2)).
Answer:
1.324
Step-by-step explanation:
Answer:
x = 0.96
Step-by-step explanation:









Answer: x = 0.96
To remove the parentheses, you just distribute.
So, it will become 3ax + 3b^2 - 3c +2. I don't think there is any like term in this expression.