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babunello [35]
3 years ago
10

Find the equation of the linear function represented by the table below in slope-intercept form.

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

y = 4x - 1

Step-by-step explanation:

The y-intercept is -1 , and the slope is 4

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A mapping statement is a way of describing a _____ of a figure.
Pepsi [2]

A mapping system is a way of describing a C. Preimage of a figure. Mapping statements are known to define the range of data sources thus showing all the data. While on the other hand, preimage (in Mathematics) meaning is that set of all the elements of the domain that maps to the members of S.

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3 0
3 years ago
What property is this (8x5) x 10=8x(5x10)
sertanlavr [38]

Answer:

Associative

you can change (8*5) *10 to (8*10) *5

You can change 8*( 5*10) to 10* (8*5)


8 0
3 years ago
2/5 times ( -10)=?<br> ?=
Rudiy27

\frac{2}{5}  \times ( - 10)

2 \times  - 2

- 4

6 0
2 years ago
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Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the
Rama09 [41]

<em><u>Question:</u></em>

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s   2s   3s   4s

<em><u>Answer:</u></em>

It takes 2 seconds for object to hit the ground

<em><u>Solution:</u></em>

<em><u>The given equation is:</u></em>

h(t) = -16t^2 + v_0t+h_0

Initial velocity = 27 feet/sec

h_0 = 10\ feet

Therefore,

h(t) = -16t^2 +27t+10

At the point the object hits the ground, h(t) = 0

-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0

Solve by quadratic formula,

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0
3 years ago
Can someone plz help me I’m being timed!!!!
nikklg [1K]

Answer:

49  and 58

Step-by-step explanation:

pls brainliest

7 0
2 years ago
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