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zubka84 [21]
4 years ago
10

5x+4y=-14 3x+6y=6 solve the system below by the elimation​

Mathematics
1 answer:
lana66690 [7]4 years ago
8 0

Answer:

y = 4

x = -6

Step-by-step explanation:

multiply first equation by 3

3×(5x+4y)= -14 ➡ 15x + 12y = -42

multiply second equation by -5

-5×(3x+6y)= 6➡ -15x -30y = -30

now add both equations up

15x +12y -15x -30y = -42 -30 (15x will eliminate -15x)

-18y = -72

y = 4 use this to find value of x

3x + 6×4 = 6 ➡ ex = -18 ➡ x = -6

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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)
andrezito [222]

Answer:

a) \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325

b) The lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

Step-by-step explanation:

a) To simplify the expression \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right) you must:

Apply Difference of Two Squares Formula: \left(a+b\right)\left(a-b\right)=a^2-b^2

a=18,\:b=\tan \left(x\right)

\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)

324-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Apply the Pythagorean Identity 1+\tan ^2\left(x\right)=\sec ^2\left(x\right)

From the Pythagorean Identity, we know that 1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Therefore,

324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325

b) According with the below graph, the lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

3 0
4 years ago
Simplify and Evaluate
zalisa [80]
\dfrac{2^{-1} + 5^{-1}}{10^{-1} - 5^{-2}} =

= \dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{5^2}}

=\dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{25}}

=\dfrac{\frac{5}{10} + \frac{2}{10}}{\frac{5}{50} - \frac{2}{50}}

=\dfrac{\frac{7}{10}}{\frac{3}{50}}

= \frac{7}{10} \times \frac{50}{3}

= \frac{7}{1} \times \frac{5}{3}

= \frac{35}{3}


4 0
3 years ago
A rectangle has an area of 36 inches squared. Write an equation to show how the length (l) varies inversely the width (w).
Anastaziya [24]
Start with the first sentence, and the definition of the area of a rectangle:
l * w = 36

Rewrite the equation to get
l = 36 / w
or
w = 36 / l
Either one shows the inverse relationship between w and l.

Assuming the last part wants you to write an equation for an x-y graph, the equation would be
y = 36 / x
8 0
3 years ago
22 more than four times a number is less than 82 <br><br> (Inequality equation)
Tanzania [10]

22^4c-82. Is the equation I think you are looking for.

5 0
4 years ago
ILL GIVE BRAINLIEST! PLEASE HELP I DONT UNDERSTAND!
blsea [12.9K]

Answer:

S₁₅ = 645

Step-by-step explanation:

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Using the nth term formula a_{n} = 5n + 3 , then

a₁ = 5(1) + 3 = 5 + 3 = 8

a₂ = 5(2) + 3 = 10 + 3 = 13 , then

d = a₂ - a₁ = 13 - 8 = 5

Thus

S₁₅ = \frac{15}{2} [ (2 × 8) + (14 × 5) ]

     = 7.5( 16 + 70)

     = 7.5 × 86

     = 645

7 0
3 years ago
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