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lisabon 2012 [21]
3 years ago
12

Please and thankyou (:

Mathematics
1 answer:
den301095 [7]3 years ago
6 0

Let's evaluate the ratio test:

\dfrac{a_n}{a_{n-1}}=\dfrac{3^{n+1}}{3n+1}\cdot\dfrac{3(n-1)+1}{3^n}=\dfrac{3\cdot3^n}{3n+1}\cdot\dfrac{3n-2}{3^n} = \dfrac{9n-6}{3n+1}

The limit as n \to\infty of this quantity is 3, which is more than 1. So, the series diverges.

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The distance travelled is 10 m

The velocity gained at the end of the time is 2 m/s

<h3>Motion</h3>

From the question, we are to determine distance travelled and the velocity gained

From one of the equations of motion for <u>linear motion</u>, we have that

S = ut + 1/2at²

Where S is the distance

u is the initial velocity

t is the time taken

and a is the acceleration

First, we will calculate the acceleration

Using the formula,

F = ma

Where F is the force

m is the mass

and a is the acceleration

∴ a = F/m

Where F is the force

and a is the acceleration

From the given information,

F = 50 N

m = 250 kg

Putting the parameters into the equation,

a =  50/250

a = 0.2 m/s²

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From the information,

u = 0 m/s (Since the object was initially at rest)

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S = 10 m

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v = u + at

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Learn more on Motion here: brainly.com/question/10962624

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Step-by-step explanation:

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