Maximize and minimize p = x + 2y subject to
1 answer:
Answer:
Minimum: (x, y, p) = (6, 0, 6)
Maximum: (x, y, p) = (2, 8, 18)
Step-by-step explanation:
I find it easiest to solve problems like this graphically. In the attached graph, we have reversed all of the inequalities, so that the feasible region is white, rather than shaded 4 times. I find this makes it much easier to see. The dashed lines indicate that the boundary lines are part of the feasible region (not part of the space outside the feasible region).
Once the slope of the objective function is determined, it is easy to identify the vertices of the feasible region that will maximize or minimize it. P is minimized when its line is closest to the origin. It is maximized when it is farthest away from the origin.
We find ...
p is minimized at (x, y) = (6, 0), where p = 6.
p is maximized at (x, y) = (2, 8), where p = 18.
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Answer: OPTION D:
Step-by-step explanation:
By definiton, fractions have the following form:
Where "a" is called numerator and "b" is the denominator. The numerator and the denominator are Integers.
In order to solve this exercise you need to remember de Division of fractions:
In this case, according to the information given in the exercise, you know that of rubies are divided into 4 lots.
Therefore, in order to calculate the weight in pounds of each lot, you need to divide by 4.
Then, you get the following result:
As you can notice, this result matches with the Option D.