Answer:
0.239 T
Explanation:
Applying,
F = Bvqsin∅................ Equation 1
Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.
make B the subject of the equation
B = F/(vqsin∅)................. Equation 2
From the question,
Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)
Constant: q = 1.602 x 10⁻¹⁹ C
Substitute into equation 2
B = 1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)
B = 1.15×10⁻¹³/(4.806×10⁻¹³)
B = 0.239 T.
Hence the magnetic field = 0.239 T
Answer:
block 2 or 4
because of the distribution of weight and force being applied to the object
Answer:
Average acceleration, 
Explanation:
Given that,
Initial velocity, u = 0 km/h
Final velocity, v = 100 km/h = 27.77 m/s
Time, t = 10 s
We need to find the average acceleration of the vehicle. It is given by the change in velocity divided by time. Som,

So, its average acceleration is
.
Answer:

Explanation:
means initial angular velocity, which is 0 rev/min
means final angular velocity, which is 
t means time t= 3.20 s
one revolution is equivalent to 2πrad so the final angular velocity is:
= (2π/60) *2.513*10^{4} rad/s
= 2628.5 rad/s
so the angular acceleration, α will be:
α = 2628.5 rad/s / 3.20 s

so the rotational motion about a fixed axis is:
+ 2αΔTita where ΔTita is the angle in radians
so now find the ΔTita the subject of the formula
ΔTita = 


Answer:
3 is the GCF for all these numbers if thats what you're asking