The answer would be B the method of rock formation
Question seems to be missing. Found it on google:
a) How long is the ski jumper airborne?
b) Where does the ski jumper land on the incline?
a) 4.15 s
We start by noticing that:
- The horizontal motion of the skier is a uniform motion, with constant velocity

and the distance covered along the horizontal direction in a time t is

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity
and constant acceleration
(where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is
below the horizontal
This happens when:

Substituting and solving for t, we find:

b) 143.6 m
Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:


The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

Answer:
Final momentum after a head on collision is -2kgm/
Explanation:
One ball moves to the right and the other moves opposite and momentum is a vector quantity so that considering the direction
Initial momenta are P₁=2x3=6kgm/s P₂=4x(-2)=-8kgm/s
Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s
Acceleration = change in velocity/change in time
= (30 - 20) / 10 - 0
= 10 / 10
Acceleration = 1 m/s²