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Sever21 [200]
4 years ago
13

Can someone help me solve this? i don't want the direct answer, just the way to solve it.

Mathematics
2 answers:
adell [148]4 years ago
5 0
Graph it by the y intercept.. eays simple math btw the answer is C
Kaylis [27]4 years ago
3 0
Plus y into the second equation.
2x+6(-1/3x+2/3)=4
solve
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How to solve part ii and iii
iragen [17]

(i) Given that

\tan^{-1}(x) + \tan^{-1}(y) + \tan^{-1}(xy) = \dfrac{7\pi}{12}

when x=1 this reduces to

\tan^{-1}(1) + 2 \tan^{-1}(y) = \dfrac{7\pi}{12}

\dfrac\pi4 + 2 \tan^{-1}(y) = \dfrac{7\pi}{12}

2 \tan^{-1}(y) = \dfrac\pi3

\tan^{-1}(y) = \dfrac\pi6

\tan\left(\tan^{-1}(y)\right) = \tan\left(\dfrac\pi6\right)

\implies \boxed{y = \dfrac1{\sqrt3}}

(ii) Differentiate \tan^{-1}(xy) implicitly with respect to x. By the chain and product rules,

\dfrac d{dx} \tan^{-1}(xy) = \dfrac1{1+(xy)^2} \times \dfrac d{dx}xy = \boxed{\dfrac{y + x\frac{dy}{dx}}{1 + x^2y^2}}

(iii) Differentiating both sides of the given equation leads to

\dfrac1{1+x^2} + \dfrac1{1+y^2} \dfrac{dy}{dx} + \dfrac{y + x\frac{dy}{dx}}{1+x^2y^2} = 0

where we use the result from (ii) for the derivative of \tan^{-1}(xy).

Solve for \frac{dy}{dx} :

\dfrac1{1+x^2} + \left(\dfrac1{1+y^2} + \dfrac x{1+x^2y^2}\right) \dfrac{dy}{dx} + \dfrac y{1+x^2y^2} = 0

\left(\dfrac1{1+y^2} + \dfrac x{1+x^2y^2}\right) \dfrac{dy}{dx} = -\left(\dfrac1{1+x^2} + \dfrac y{1+x^2y^2}\right)

\dfrac{1+x^2y^2 + x(1+y^2)}{(1+y^2)(1+x^2y^2)} \dfrac{dy}{dx} = - \dfrac{1+x^2y^2 + y(1+x^2)}{(1+x^2)(1+x^2y^2)}

\implies \dfrac{dy}{dx} = - \dfrac{(1 + x^2y^2 + y + x^2y) (1 + y^2) (1 + x^2y^2)}{(1 + x^2y^2 + x + xy^2) (1+x^2) (1+x^2y^2)}

\implies \dfrac{dy}{dx} = -\dfrac{(1 + x^2y^2 + y + x^2y) (1 + y^2)}{(1 + x^2y^2 + x + xy^2) (1+x^2)}

From part (i), we have x=1 and y=\frac1{\sqrt3}, and substituting these leads to

\dfrac{dy}{dx} = -\dfrac{\left(1 + \frac13 + \frac1{\sqrt3} + \frac1{\sqrt3}\right) \left(1 + \frac13\right)}{\left(1 + \frac13 + 1 + \frac13\right) \left(1 + 1\right)}

\dfrac{dy}{dx} = -\dfrac{\left(\frac43 + \frac2{\sqrt3}\right) \times \frac43}{\frac83 \times 2}

\dfrac{dy}{dx} = -\dfrac13 - \dfrac1{2\sqrt3}

as required.

3 0
2 years ago
What is the LCM of 11 and 44
Katarina [22]
The Least common multiple of 11 and 44 is 44
7 0
3 years ago
Read 2 more answers
0.045Decimal to percentage
yulyashka [42]

Answer: 4.5%

Step-by-step explanation: o convert from decimal to percent, just multiply the decimal value by 100. In this example we have: 0.045 × 100 = 4.5% (answer).

3 0
2 years ago
Solve for x. <br><br> 3x = 2/5
Elena-2011 [213]
X = 0.4/3
x = 13
if answer is wanted in decimal form.
6 0
4 years ago
The quality of computer disks is measured by sending the disks through a certifier which counts the number of missing pulses. A
Westkost [7]

Answer:

Poisson distribution.

Step-by-step explanation:

We have the mean number of missing pulses per disk, which means that the distribution for X, the number of missing pulses, will be the Poisson distribution.

It is not the binomial distribution because we are not given the probability of a missing pulse on a disk, but the mean number of missing pulses.

4 0
3 years ago
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