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4 years ago

If a fraction can be written as a repeating decimal,only one digit can repeat over and over, without end. True or false?

Mathematics

1 answer:

steposvetlana [31]4 years ago

8 0

True. it can only be written as one repeating number because eventually, a set of numbers would cancel out i think

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HERE IS THE TEXT THERE IS MORE THO

Ostrovityanka [42]

Answer:

What exactly is this for?

8 0

3 years ago

A gambler claims that horses in a horse race that start closer to the rail have an advantage over horses that start further from

k0ka [10]

Answer:

Hence, the p-value ( 0.699986) > 0.05, FAIL TO REJECT THE NULL HYPOTHESIS

there is no significant evidence that starting position is a factor in horse races

Step-by-step explanation:

Given the data in the question;

Starting position: 1 2 3 4 5 6

# of Winners: 25 22 18 19 21 15

Mean x" (E) = (25+22+18+19+21+15)/6 = 120/6 = 20

Observed/Expected value table;

O E ((O-E)²) / E

25 20 1.25

22 20 0.2

18 20 0.2

19 20 0.05

21 20 0.05

15 20 1.25

∑ 3

so using chi square = ∑(((O-E)²) / E) = 3

DF = n-1 = 6-1 = 5

then, the critical chi square value is;

significance level = 0.05

chi square( critical ) = 11.07049769

from table;

p - value = 0.699986

Hence, the p-value ( 0.699986) > 0.05, FAIL TO REJECT THE NULL HYPOTHESIS

there is no significant evidence that starting position is a factor in horse races

8 0

3 years ago

PLEASE HELP!! URGENT

Schach [20]

Answer:

The answer is option 1.

Step-by-step explanation:

You have to apply Tangent Rule, tanθ = opposite/adjacent. Then, you have to substitute the following values into the formula :

$tan(θ) = \frac{oppo.}{adj.}$

$let \: θ = 25.7 \: , \: oppo. = h \: , \: adj. = 532$

$\tan(25.7) = \frac{h}{532}$

$532 \tan(25.7) = h$

$h = 256 \: feet \: (3s.f)$

8 0

4 years ago

Read 2 more answers

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

3 years ago

For what values of a are the following statements true: |a+5|=a+5

sdas [7]

Answer:

a≥0

Step-by-step explanation:

The equation on the left is absolute value so all values plugged in will be positive but on the other side if a negative was plugged in it would still be negative and thus result in a lower sum than the other side. For example:

|-2+5|=-2+5

7=3

this is untrue.

the equation would only be true if the a values were positive.

5 0

3 years ago