Answer:
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Step-by-step explanation:
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em>
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Answer:
Step-by-step explanation:
The slope formula is useful for this.
m = (y2 -y1)/(x2 -x1)
__
<u>First line</u>:
m = (-9 -(-9))/(9 -(-6)) = 0/15 = 0
The slope of the first line is zero.
__
<u>Second line</u>:
m = (-5-1)/(4 -4) = -6/0 = undefined
The slope of the second line is undefined.
_____
It is always a good idea to apply a little critical thinking to the given information. Here, you observe that the y-coordinates of the first pair of points are the same. That means this is a horizontal line, with a slope of 0.
Similarly, you observe that the x-coordinates of the second pair of points are the same. That means this is a vertical line, with undefined slope.
4 seconds, so whatever the letter is for the answer I have provided, select it
Google the answer thats smarter
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>