Choose the most correct statement given that Quadrilateral ABCD has vertices A(2, 1), B(2, 4), C(7, 4), and D(6, 1)?

The length of an aquarium, which has the form of a rectangular solid, is equal to 5 decimeters, and the width is 4/5 the length.

Oksanka [162]

Answer:

Given the statement: The length of an aquarium, which has the form of a rectangular solid, is equal to 5 decimeters, and the width is 4/5 the length.

Since, aquarium is in the form of a rectangular solid.

Length of an aquarium(l) = 5 dm

Width of an aquarium(w)= $\frac{4}{5}\times 5 = 4 dm$

It is also given that when you put 40 liters of water into the aquarium, it was full to $\frac{2}{3}$ its volume.

Volume of Rectangular solid(V) is given by;

$V = l \times b \times h$ where l is the length , w is the width and h is the height of the rectangle respectively.

Volume(V) of an aquarium = $\frac{3}{2} \times 40 = 60$ liter.

Using volume formula to calculate the height(h);

$60 = 5 \times 4 \times h$

$60 = 20h$

Divide both sides by 20 we get;

h = 3 dm [ 1 liter = 1 cubic dm]

We have to find the what part of length makes up the height of the aquarium.

$h = \frac{3}{5} l$ where l = 5 dm

therefore, $\frac{3}{5}$ part of the length makes up the height of the aquarium.

8 0

4 years ago

A baker sells cookies for $1.50 each. If a minimum of two dozen cookies is ordered, the baker gives a 40% discount for each cook

kenny6666 [7]

I don't see the expression below.
Since the 40% discount applies to the number of cookies sold above 2 dozen, or 24, then if the number of cookies is c, then c - 24 is the number of cookies above 2 dozen. Answer is B.

7 0

3 years ago

Which statement listed below illustrates the reflexive property of congruence

Vlad1618 [11]

Option D:

$\triangle K L M \cong \triangle K L M$

Solution:

Reflexive property of congruence:

<em>Reflexive property of congruence means the geometric figure is congruent to itself.</em>

Option A: If $\triangle K L M \cong \triangle P Q R \text { and } \triangle P Q R \cong \triangle S T U \text { , then } \triangle K LM\cong \triangle S T U$