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4 years ago

Identify the solution set of the given inequality using the given replacement set.

Mathematics

1 answer:

scoundrel [369]4 years ago

3 0

Another user previously answered this same question and had a good rating, his answer was as follows:

"{-9; -6.5; -5.2}"

Which I suppose would be answer D.
- Hope it helps.

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Why are all of you getting answers from students, you know you guys are cheating

jeyben [28]

Answer:

it's not cheating, it's helping out fellow students and explaining it to them.

Step-by-step explanation:

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3 years ago

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Reduced form of 2ab^2-a^2 b^2/5

Ket [755]

Answer:

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

Step-by-step explanation:

Given the expression

$2ab^2-\frac{a^2b^2}{5}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}$

$2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{2ab^2\cdot \:5-a^2b^2}{5}$

$=\frac{10ab^2-a^2b^2}{5}$

Thus,

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

7 0

3 years ago

Please complete the following with explanation:

satela [25.4K]

Answer:

Step-by-step explanation:

Factor 25p^ 2 -81q^ 2 : (5p + 9q)(5p - 9q)

Steps

25p ^ 2 - 81q ^ 2

=(5p)^ 2 -(9q)^ 2

Apply Difference of Two Squares Formula: x ^ 2 - y ^ 2 = (x + y)(x - y)

(5p) ^ 2 - (9q) ^ 2 = (5p + 9q)(5p - 9q)

=(5p+9q)(5p-9q)

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3 years ago

An angle is formed by:

djverab [1.8K]

Answer: an angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle.

Step-by-step explanation:

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3 years ago

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Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

kow [346]

If the perimeter is 9 inches, each side is 3 inches.

The height of an equilateral triangle splits the triangle in two right sub-triangles: for example, consider a triangle ABC and the height AH starting from A, perpendicular to BC.

The triangle AHC is a right triangle, whose legs are AH and HC, and whose hypotenuse is AC.

AH is half the side, and AC is a side. So, we can use the Pythagorean theorem to find the height:

$AH = \sqrt{AC^2-AH^2}=\sqrt{l^2-\dfrac{l^2}{4}}=\dfrac{\sqrt{3}l}{2}$

So, the area is

$\dfrac{AH\cdot HC}{2} = \dfrac{l\cdot\frac{\sqrt{3}l}{2}}{2} = \dfrac{l^2\sqrt{3}}{4} = \dfrac{9\sqrt{3}}{4}$

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4 years ago