Two similar prisms have heights of 4 cm and 10 cm. what is the ratio of their surface areas?

Help picture below problem 19

frutty [35]

Answer:

I think the amswer is C not 100% shere

Step-by-step explanation:

6 0

2 years ago

One mixture contains 6 fluid Ounces of water and 10 fluid Ounces of vinegar. A second mixture

Nadya [2.5K]

Answer:

The mixtures are not proportional.

3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.

its =3

Step-by-step explanation:

The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.

Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5

Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.

Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4

Therefore, the mixtures are not proportional.

Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.

So,

⇒ 12 + x = 15

⇒ x = 3 fluid ounces.

Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer

5 0

1 year ago

the waiter places a bowl of soup in front of lacy in a counterclockwise direction she passes the soup 90° the person receiving t

dybincka [34]

haifia is the answer did it on test

5 0

3 years ago

An airplane is 1440 above a buoy in the ocean. The buoy is 15 miles away from the mainland What is the diagonal distance in mite

Crazy boy [7]

Answer:

1440.08 mi

Step-by-step explanation:

Pythagorean Theorem:

$\sqrt{1440^{2}+15^{2} }$ = 1440.08

6 0

2 years ago

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 55, \pi = \frac{24}{55} = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - \frac{0.07}{2} = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574$

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0

3 years ago