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motikmotik
3 years ago
6

Please help!!!!!!!!!

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0

Answer:

Step-by-step explanation:

it is C

Anvisha [2.4K]3 years ago
7 0

Answer:

your answer is 3.)

Step-by-step explanation:

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PLEASE HELP FAST
Pachacha [2.7K]
C, I was in class this morning and we say the formula for this is $6000 x 1.15 to the power of 5. That is $12068.14

Hope I could help :)

5 0
3 years ago
First 5 multiples of 7
GarryVolchara [31]

Answer: 0, 7, 14, 21, and 28

Step-by-step explanation: To find the first 5 multiples of 7, multiply 7 by the first 5 whole numbers which I have done for you in the image attached.

To quickly review, the set of whole numbers are shown below.

{0, 1, 2, 3, 4, ...}

The numbers that I have highlighted in green will be your first 5 multiples.

7 0
3 years ago
What do you times to get the perimeter of a rectangle
Irina-Kira [14]
You add all the sides together for perimeter
6 0
3 years ago
Read 2 more answers
9 m<br> 3 m<br> 3 m<br> What is the area, in square meters, of the shaded region in the diagram?
NeTakaya

Answer:

Notice that the side length of the square is  38 m.

area of square  =  (side length)2  =  (38 m)2   =   1444 m2

Notice that the diameter of the circle is  38 m .

And its radius  =  diameter / 2   =   38m / 2   =   19 m

area of circle  =  pi * radius2  =  pi * (19m)2  =  pi * 361 m2   ≈   1133.54 m2

So......

area of shaded region  =  area of square - area of circle

area of shaded region  ≈       1444 m2     -  1133.54 m2

area of shaded region  ≈    310.46 m2

Step-by-step explanation:

Notice that the side length of the square is  38 m.

area of square  =  (side length)2  =  (38 m)2   =   1444 m2

Notice that the diameter of the circle is  38 m .

And its radius  =  diameter / 2   =   38m / 2   =   19 m

area of circle  =  pi * radius2  =  pi * (19m)2  =  pi * 361 m2   ≈   1133.54 m2

So......

area of shaded region  =  area of square - area of circle

area of shaded region  ≈       1444 m2     -  1133.54 m2

area of shaded region  ≈    310.46 m2

3 0
3 years ago
I need help on how to do these types of problems
aivan3 [116]
#1 
Lets x = number of adult tickets
Lets y = number of children tickets

equation 1: 8x + 4y = 5040
equation 2: x + y = 680

solve them by using substitution
 x + y = 680 
 x = 680 - y

substitute  x = 680 - y into  8x + 4y = 5040

8(680 - y) + 4y = 5040
5440 - 8y + 4y = 5040
-4y = 5040 - 5440
-4y = -400
   y = 100

x = 680 - y
x = 680 - 100
x = 580

Answer:

There were 580 adults and 100 children at the last Miller's home basketball game.

#2
Similar to the #1

Lets x is the number of people riding school bus
Lets y is the number of people riding luxury charter bus

equation 1: x + y = 65
equation 2: 8x + 15y = 611


6 0
3 years ago
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