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3 years ago

The area of the rectangle is 24 inches. How much longer is its length than its width?

1 answer:

8 0

I Belive That There Can't Be 3 Numbers In A Rectangle Because At The Top You Get 24 And 6 And I Think It Is BxH One Half Times Base Times Height So 2xBxH .

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X - (6.9) = 42.8<br><br> x = 42.8 +

Harman [31]

I hope this helps you

x=42.8+6.9

x=49.7

4 0

3 years ago

Read 2 more answers

A system consisting of one original unit plus a spare can function for a random amount of time X. If the density of Xis given (i

eimsori [14]

Answer:

0.2397

Step-by-step explanation:

Given data:

fX(x) = Cxe^(−x/2) if x >0 0 otherwise, where C > 0 is some constant.

The probability that the system functions for at least 5 months

= 0.2397

attached below is a detailed solution

3 0

2 years ago

The formula for the volume of a cone is V=1/3 pi r2h the radius r of the cone may be expressed as

Naily [24]

r = √(3V/πh)

multiply both sides by 3 to eliminate the fraction

πr²h = 3V ( divide both sides by πh )

r² = 3V/ πh ( take the square root of both sides )

r = √(3V/πh)

3 0

3 years ago

Read 2 more answers

A triangle has vertices at coordinates $(1, 2), (7, 10)$ and $(1, 12)$. What is the number of units in the length of the shortes

const2013 [10]

Answer:

The number of units in the length of the shortest side of the triangle is 6.325 units or 2 sqrt 10.

7 0

3 years ago

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

6 0

3 years ago