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Nimfa-mama [501]

3 years ago

8

A classroom's length is 3m less than two times its width. The classroom has a length of 9m. Solve an equation to determine the w

idth of the classroom.

1 answer:

Ugo [173]3 years ago

8 0

The equation would be 2w-3=9. Do the inverse operation for '3' on both sides of the equation. Then do the inverse operation on both sides of the equation for '2w'.

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Solve:<br> |x -0.5| < 12

never [62]

Your answer should be -11.5

6 0

3 years ago

The endpoints of ab are a(1,4) and b(6,-1). If point c divides ab in the ratio 2:3, the coordinates of c are ?. If point d divid

aliya0001 [1]

Answer:

see explanation

Step-by-step explanation:

Find the coordinates of c using the section formula

$x_{c}$ = $\frac{(3(1)+(2(6)}{2+3}$ = $\frac{3+12}{5}$ = 3

$y_{c}$ = $\frac{(3(4))+(2(-1))}{2+3}$ = $\frac{12-2}{5}$ = 2

coordinates of c = (3, 2)

Similarly to find the coordinates of d

$x_{d}$ = $\frac{x(2(1))+(3(3))}{3+2}$ = $\frac{2+9}{5}$ = $\frac{11}{5}$

$y_{d}$ = $\frac{(2(4))+(3(2))}{3+2}$ = $\frac{8+6}{5}$ = $\frac{14}{5}$

coordinates of d = ( $\frac{11}{5}$ , $\frac{14}{5}$ )

4 0

3 years ago

Read 2 more answers

N/5 greater than or equal to 11

avanturin [10]

N/5 is greater than 11

5 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

<u></u> $\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

<u></u> $\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago

In one day, a book store earned $253 in sales for 4 copies of a new cookbook and 5 copies of a new science fiction novel. On the

Aloiza [94]

Answer: cookbook $40 and science $15

Step-by-step explanation:

5 0

2 years ago

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