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avanturin [10]
3 years ago
11

If 153=2(z+z)n153=2(z+z)n153, equals, 2, left parenthesis, z, plus, z, right parenthesis, n, then what is the value of 2n(2z)-19

32n(2z)−1932, n, left parenthesis, 2, z, right parenthesis, minus, 193?
Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
What you must do for this case is to rewrite the first expression to find its value.
 We have then:
 153 = 2 (z + z) n
 Rewriting:
 153 = 2n2z
 Then,
 2n (2z) -193
 Substituting
 153-193 = -40
 Answer:
 the value of 2n (2z) -193 is
 -40
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1+2-3+4+5-6+7+8-9...+97+98-99
zaharov [31]

Answer:

  1584

Step-by-step explanation:

The sum of this sequence can be found a number of ways. One way is to recast it as the series whose terms are groups of three terms of the given series.

__

<h3>series of partial sums</h3>

The partial sums, taken 3 terms at a time, are

  1+2-3 = 0

  4+5-6 = 3

  7+8-9 = 6

...

  97+98-99 = 96

So the original series is equivalent to ...

  0 +3 +6 +... +96 = 3×1 +3×2 +... +3×32 = 3×(1 +2 +... +32)

That is, the sum is 3 times the sum of the consecutive integers 1..32.

__

<h3>consecutive integers</h3>

The sum of integers 1..n is given by the equation ...

  s(n) = n(n+1)/2

__

<h3>series sum</h3>

Using this to find the sum of our series, we find it to be ...

  series sum = 3 × (32)(33)/2 = 1584

_____

<em>Alternate solution</em>

The given series is the sum of integers 1-99, with 6 times the sum of integers 1-33 subtracted. That is, ...

  1 + 2 - 3 + 4 + 5 - 6 = 1+2+3+4+5+6 -2(3 +6) = 1+2+3+4+5+6 -6(1+2)

Continuing on to ...97 +98 -99 gives the result s(99) -6s(33).

Computed that way, we find the sum to be ...

  (99)(100)/2 -6(33)(34)/2 = 4950 -3366 = 1584

3 0
2 years ago
Aqa Q8 Write down all the whole numbers that are between 20 and 50 and have a difference of 4 between their digits.
adelina 88 [10]

Answer:

The first 100 whole numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, ...

Step-by-step explanation:

3 0
3 years ago
If the area of the outer square is 4x2, then the area of the inner square is
konstantin123 [22]
<span>Answered by the following sums - Outer square area = 4x^2 side of the square = 2x which is equal to diameter of circle == diameter of inner square. radius of circle = x diameter of outer square = 2*sqrt(2)*x consider side of inner square = a so a^2 + a^2 = (2x)^2 2a^2 = 4x^2 a = x*sqrt(2) So area of inner square will be = 2x^2</span>
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3 years ago
Find the inverse for the relationship (1,-3 ), (-2, 3), (5, 1), (6, 4)
Tatiana [17]

Answer:

you just make the x values the y values and the y values the x values

Step-by-step explanation:

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8 0
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In the figure, RQS QLK.<br><br><br> What is the value of x?<br><br> 36<br> 72<br> 108<br> 144
Lena [83]
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3 0
3 years ago
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