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Scrat [10]
3 years ago
10

Ocean waves move in parallel lines toward the shore. The figure shows Sandy Beaches windsurfing across several waves. For this p

roblem, think of Sandy’s wake as a line. m∠1 = (2x + 10)° and m∠2 = (4y − 30)°. Find x and y

Mathematics
2 answers:
Trava [24]3 years ago
6 0

If you look at the figure, the angle marked red is equal to 70° because vertical angles are equal. So, that also means that the opposite angle 2 is also 70°. So, the first equation is:

70 = 5x + y

Next, the green angle as marked is equal to

Green angle = 180 - 70 = 110

Being vertical angles, angle 1 is then equal to 110°. So,the second equation is

110 = 5x + 3y

Subtract the two equations:

   5x + y = 70

-  5x + 3y = 110

________________

          -3y = -40

             y = -40/-3 = 13.33°

Substituting y to either one of the equations,

5x + 13.33 = 70

Solving for x,

x = 11.33°

Eddi Din [679]3 years ago
3 0

Angle 2 is the same as the given angle of 70 degrees so we can solve for y:

4y-30 = 70

Add 30 to both sides:

4y = 100

Divide both sides by 4:

Y = 25

Angle 1 and angle two are supplementary angles and when added together need to equal 180:

We know angle 2 = 70, so angle 1 must equal 180-70 = 110

2x + 10 = 110

Subtract 10 from both sides:

2x = 100

Divide both sides by 2:

X = 50

The answer is:

X = 50, y = 25

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Answer:

Step-by-step explanation:

No

2(3x-6)=6x-12

2(3x)-6=6x-6

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The equation ℎ = −162 + 32 + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown up
Maru [420]

Answer:

time = 1secs

<em>Max height = 25metres</em>

Step-by-step explanation:

Let the equation that models the height of the ball be expressed as;

h(t) = −16t^2 + 32t + 9

t is the time in seconds

The velocity of the ball at its maximum height is zero i.e dh/dt = 0

dh/dt = -32t + 32

0 = -32t + 32

32t = 32

t = 32/32

t = 1 seconds

The ball will reach its maximum height after 1 seconds.

Get the maximum height reached. Substitute t = 1 into the modeled function;

h(t) = −16t^2 + 32t + 9

h(1) = −16(1)^2 + 32(1) + 9

h(1) = −16 + 32 + 9  

h(1)= 16+9

<em>h(1) = 25</em>

<em>Hence the maximum height reached is 25metres</em>

4 0
3 years ago
You come home from Brian’s Orchard with a big brown bag of apples: 23 Granny Smiths, 14 Honey Crisp and 31 Red Delicious. What i
garik1379 [7]

Answer:

a. Probability of Pulling one of each = 0.03175

b. Probability of Pulling 4 Honey Crisp = 0.001797

Probability of 2 G.Smith = 0.1144

Probability of 1 Red Delicious = 0.4559

Step-by-step explanation:

Given

Granny Smiths = 23

Honey Crisp = 14

Red Delicious = 31

Required

- Probability of Pulling out one of each

- Probability of Pulling out 4 Honey Crisp; 2 Granny Smiths; 1 Red Delicious

First, the total number of apple needs to be calculated.

Total = Granny Smiths + Honey Crisp + Red Delicious

Total = 23 + 14 + 31

Total = 68

Probability of Pulling 1 of each

= P(Granny Smiths) and P(Henry Ford) and P(Red Delicious)

- Granny Smiths;

This is calculated by dividing number of Granny Smiths apples by total number of apples.

Probability = 23/68

Similarly,

Probability of Pulling Honey Crisp= Number of Honey Crisp divided by total

Probability = 14/68

Probability = 7/34

Probability of Pulling Red Delicious = Number of Red Delicious divided by total

Probability = 31/68

So, Probability of Pulling 1 of each = 23/68 * 7/34 * 31/68

Probability = 4991/157216

Probability = 0.03175

Probability of Pulling out 4 Honey Crisp;

= P(Honey) * P(Honey) * P(Honey) * P(Honey)

= (P(Honey))⁴

= (7/34)⁴

= 2401/1336336

= 0.001797

Probability of Pulling 2 Granny Smiths;

= P(Granny) * P(Granny)

= (P(Granny))²

= (23/68)²

= 529/4624

= 0.1144

Probability of 1 Red Delicious

= number of red delicious divided by total

= 31/68

= 0.4559

3 0
3 years ago
Jan accidently ran 7 minutes longer than he was supposed to. Write an expression for the total amount of time Jan ran if she was
Ilia_Sergeevich [38]
Jan ran m + 7 minutes.
7 0
3 years ago
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