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wariber [46]
3 years ago
6

PLEASE HELP

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0
Distance || times (h)
7 1/2 || 1/2
15 || 1
22 1/2 || 1 1/2
30 || 2
37 1/2 || 2 1/2


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f(x) = 4x^2+2x+6 What is the value of the discriminant of f? How many distinct real number zeros does f have?
Sauron [17]

Answer:

The value of Discriminant of the function is -92

It has ZERO distinct real number zeros.

Step-by-step explanation:

Given:

f(x)=4x^{2} +2x+6

Which is a Quadratic Equation in the general form of

ax^{2}+bx+c=0

where a,b and c are constants.So on comparing the given equation with general form we get,

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Formula for discriminant we have

Discriminant=b^{2}-4ac\\ =2^{2}-4(4)(6)\\ =4-96\\=-92

now for zeros  we have

x=\frac{-b+\sqrt{b^{2-4ac} } }{2a} \\or\\x=\frac{-b-\sqrt{b^{2-4ac} } }{2a} \\

on substituting these values we get

x=\frac{-2+\sqrt{-92} }{8}

or

x=\frac{-2-\sqrt{-92} }{8}

the term \sqrt{-92} is imaginary

hence the zeros are not real number

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