Question

WILL GIVE 20 POINTS! PLEASE PLEASE ANSWER THIS!!!

Answer 1

Answer:

∠ KAL = 90° (Proved)

Step-by-step explanation:

See the attached diagram.

As KLMN is a parallelogram, so ∠K + ∠ L = 180°

⇒ $\frac{1}{2}\angle K + \frac{1}{2}\angle L = 90^{\circ}$ ............ (1)

Now, given that, $\angle AKL = \frac{1}{2} \angle K$ and $\angle ALK = \frac{1}{2} \angle L$

So, ∠ AKL + ∠ ALK = 90° {From equation (1)}

Now, from Δ KAL, ∠ AKL + ∠ ALK + ∠ KAL = 180°

⇒ 90° + ∠ KAL = 180°

⇒ ∠ KAL = 90° (Proved)