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snow_tiger [21]

3 years ago

11

mr.Allen estimated that 50 people at a basketball game were cheering for the vsiting team.Select all of the statement that could

represent this estimate

1 answer:

nata0808 [166]3 years ago

8 0

What are the statements?

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FREEEEEEEEEEEEEEE POIIIIIIIIIIIIIIINNNNNNNNNNNNNNNNNTS! - Brainliest - Just answer the question correctly - (be mindful of what

Mekhanik [1.2K]

Answer:

Slope=−

2.000

1.600

=−0.800

x−intercept=

4

15

=3.75000

y−intercept=

5

15

=3

Step-by-step explanation:

7 0

3 years ago

The area of a square is 72.25 inches squared. Find the length of the side and the perimeter.

Nadya [2.5K]

Answer:

8.5 inches and 34 inches

Step-by-step explanation:

Area of the square = 72.25

side² = 72.25

side = \sqrt{72.25}

Side = 8.5 in

Perimeter = 4 × side

Perimeter = 4 × 8.5 in

Perimeter = 34 in

6 0

3 years ago

Melissa collects data on her college graduating class. She finds out that of her classmates, 60% are brunettes, 20% have blue ey

Ivahew [28]

Answer:

17

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please hurry I will mark you brainliest

pantera1 [17]

Three angles are not acute

so it is false

6 0

3 years ago

Read 2 more answers

Find the first five terms of the sequence given the following recursive formula:

forsale [732]

Answer:

The first five terms are;

-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

$a_1=-3,$ , $a_2=-7$ and $a_n=a_{n-2}-2a_{n-1}$ .

When n=3, we obtain;

$a_3=a_{3-2}-2a_{3-1}$ .

$\implies a_3=a_{1}-2a_{2}$ .

$\implies a_3=-3-2(-7)$ .

$\implies a_3=11$ .

When n=4

$\implies a_4=a_{2}-2a_{3}$ .

$\implies a_4=-7-2(11)=-29$ .

When n=5

$\implies a_5=a_{3}-2a_{4}$ .

$\implies a_4=11-2(-29)=69$ .

Therefore the first five terms are;

-3,-7,11,-29,69

5 0

4 years ago