Answer: x = 1, y = - 5
Step-by-step explanation:
The given system of linear equations is expressed as
x - 2y = 11- - - - - - - - - - - - -1
- x + 6y = - 31- - - - - - - - - - - -2
We would eliminate x by adding equation 1 to equation 2. It becomes
- 2y + 6y = 11 - 31
4y = - 20
Dividing the the left hand side and the right hand side of the equation by 4, it becomes
4y/4 = - 20/4
y = - 5
Substituting y = - 5 into equation 1, it becomes
x - 2 × - 5 = 11
x + 10 = 11
Subtracting 10 from the left hand side and the right hand side of the equation, it becomes
x + 10 - 10 = 11 - 10
x = 1
The series is a convergent p-series with p = 3
<h3>How to know it is a divergent or a convergent series</h3>
We would know that a series is a convergent p series when we have ∑ 1 np. Then you have to be able to tell if the series is a divergent p series or it is a convergent p series.
The way that you are able to tell this is if the terms of the series do not approach towards 0. Now when the value of p is greater than 1 then you would be able to tell that the series is a convergent series.
The value of 
The formular for this is
∑
where n = 1
we know it is convergent because p is greater than 1. 3>1
Read more on convergent series here:
brainly.com/question/337693
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The answer is 14.4.................................
You have to try to determine the sequence, and you try two basic kind of sequences: aritymethic and geometric.
In aritmetic sequeces the relationships is that the difference between any adjacent terms is constant.
For example
´Number of term (n) Term, An
1 7
2 11
3 15
4 19
Then the relationship between adjacent terms is 19 - 15 = 4 = 15 -11 = 4 = 11 - 7 = 4.
You can find, then, a general expression that relates any term with its position.
It is An = 7 + (n-1)*4
In geometric sequences the relationship is found dividing two adjacent terms, because the ratio is constant.
For example:
Number of term Term
1 10
2 20
3 40
4 80
You can then find the relation as: 20/10 = 2 = 40/20 = 2 = 80/40 = 2.
In this case the general term is An = 10 * 2^ (n-1)
