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2 years ago

Part 1: Celebration!

Mathematics

2 answers:

dusya [7]2 years ago

8 0

Answer:

what

Step-by-step explanation:

Alexus [3.1K]2 years ago

4 0

Answer: oh my god I did this but I failed it miserably lol, there is a video that you can watch on the toolbox that will guide you through.

Step-by-step explanation:

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Solve by any method (graphing, substitution, linear combination) <br> y=x−7 <br> 5x+2y=7

Virty [35]

Answer:

(x, y) = (3, -4)

Step-by-step explanation:

See the attached for a graph.

3 0

3 years ago

In Exercise sketch the graph of the function.<br> f(x) = ex + 2

earnstyle [38]

Answer:

slop of e

y - intercept 2

x- intercept -0.735

Step-by-step explanation:

The value of e is 2.72 and this is the slope of the graph with a y intercept of:

$y=0+2$

$y=2$

and an x intercept of:

$0=ex+2$

$x=-2/e=-0.735$

The graph is attached with the x and y intercepts

6 0

3 years ago

A scale drawing of a lake has a scale of 1 cm to 80 m. If the actual width of the lake is 1,000 m, what is the width of the lake

Andreas93 [3]

Answer: 12.5 cm

Step-by-step explanation:

Equation would be:

1:80

?:1000

So you'll just have the cross multiply the equation above to find ? ( scale drawing lake). It'll be 1000*1/80 which will be 12.5 cm.

7 0

3 years ago

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

$A=P(1+r)^x$

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

$1000=P(1+r)^0\implies P = 1000$

A = 1900 when x = 1,

$1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9$

Thus, the required function that represents the population after x days,

$A=1900(1+0.9)^x=1900(1.9)^x$

If x = 4,

The number of mosquito after 4 days,

$A=1900(1.9)^4 = 24760.99\approx 24761$

If A = 60,000,

$60000 = 1900(1.9)^x$

$\frac{600}{19}=1.9^x$

Taking log both sides,

$\log(\frac{600}{19})=x\log 1.9$

$\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4$

Thus, there will 60,000 mosquitoes after 5 days.

6 0

3 years ago

Simplify the expression below: 4 + 2³ - | -4 |

zavuch27 [327]

Answer:

Step-by-step explanation:

4 0

2 years ago