-3x from both sides so it looks like 2x=20 and divide by 2 and x=10
Add 4 to both sides
x - 4 < -3
x-4+4 < -3+4
x < 1
To graph this on a number line, plot an open circle at 1 on the number line. Do not fill in the open circle. Shade to the left of the open circle. The shaded region represents all x values smaller than 1.
The graph is shown below.
Answer:
Hence proved △ABE∼△CBF.
Step-by-step explanation:
Given,
ABCD is a parallelogram.
BF ⊥ CD and
BE ⊥ AD
To Prove : △ABE∼△CBF
We have drawn the diagram for your reference.
Proof:
Since ABCD is a parallelogram,
So according to the property of parallelogram opposite angles are equal in measure.
⇒1
And given that BF ⊥ CD and BE ⊥ AD.
So we can say that;
⇒2
Now In △ABE and △CBF
∠A = ∠C (from 1)
∠E = ∠F (from 2)
So by A.A. similarity postulate;
△ABE∼△CBF
To solve this, you will have to set up your equation as fractions:
X is to 4 as 4 is to 4+3, or 7
X/4 = 4/7
You will then cross multiply
7x = 4•4
7x = 16
Divide.
X = 2.285714...
Round to the nearest hundredth.
2.29