All categories

2 years ago

Graphic organizers reorganize information. Please select the best answer from the choices provided T F

Mathematics

2 answers:

Alex73 [517]2 years ago

6 0

Answer:

True

Step-by-step explanation:

sesenic [268]2 years ago

3 0

Answer:

The given statement is true.

Step-by-step explanation:

Graphic organizers reorganize information.

Yes this statement is true.

Graphic organizers show relationships among information .

Graphic organizers come in many different forms, with each organizer for organizing a particular type of information like the cause and effect graphic organizers that show relationships between events.

You might be interested in

Square A has a side length of (2x-7) and Square B has a side length of (-4x+18). How much bigger is the perimeter of Square B th

dusya [7]

4(2x-7)=8x-28
4(-4x+18)=-16x+72
(8x-28)-(-16x+73)

24x+45

8 0

2 years ago

Solve for x using the diagram

liraira [26]

Its bh 5 time 7 = 35 is ur hight

6 0

2 years ago

A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (> r) from th

jeyben [28]

Consider a circle with radius $r$ centered at some point $(R+r,0)$ on the $x$ -axis. This circle has equation

$(x-(R+r))^2+y^2=r^2$

Revolve the region bounded by this circle across the $y$ -axis to get a torus. Using the shell method, the volume of the resulting torus is

$\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx$

where $2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}$ .

So the volume is

$\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx$

Substitute

$x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt$

and the integral becomes

$\displaystyle4\pi r^2\int_{-\pi/2}^{\pi/2}(R+r+r\sin t)\cos^2t\,\mathrm dt$

Notice that $\sin t\cos^2t$ is an odd function, so the integral over $\left[-\frac\pi2,\frac\pi2\right]$ is 0. This leaves us with

$\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt$

Write

$\cos^2t=\dfrac{1+\cos(2t)}2$

so the volume is

$\displaystyle2\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}(1+\cos(2t))\,\mathrm dt=\boxed{2\pi^2r^2(R+r)}$

6 0

2 years ago

Please help!!! 20 points!!

Aleksandr-060686 [28]

The answer that you are looking for is C.

5 0

2 years ago

I thought of number J, and then subtracted half of it from 34.

SpyIntel [72]

Answer:

12 hope this help out dude

3 0

2 years ago