Help please, I’m not sure

16d=10<br> What’s the answer??<br> I need it quick plz

Elanso [62]

Answer: d = 5/8

Step-by-step explanation:

first, you divide both sides.

16d / 16 = 10 / 16

then, you divide and rewrite.

d = 16/10

then, reduce the fraction.

d = 5/8

4 0

3 years ago

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Which shows a reasonable estimation for 124% of 42 using the distributive property?

quester [9]

Answer:

c

Step-by-step explanation:

saya fikir jee cara tuu

4 0

3 years ago

In January of 2011, the U.S. saw an increase in gas prices. Imagine the average price per gallon was $3.12 with a standard devia

Arada [10]

Answer:

31.92%

Step-by-step explanation:

We are given;

Population mean; μ = $3.12

Sample mean; x¯ = $3.16

Sample size; n = 10

Standard deviation; σ = $0.27

Z-score formula is; z = (x¯ - μ)/(σ/√n)

z = (3.16 - 3.12)/(0.27/√10)

z = 0.04/(0.08538)

z ≈ 0.47

Now, the percent of other sample means, based on 10 gas stations, that would be greater than the one observed is;

P(x¯ > 3.12) = 1 - P(z < 0.47)

From z-table attached P(z < 0.47) = 0.68082

Thus;

P(z > 0.47) = 1 - 0.68082

P(z > 0.47) ≈ 0.3192

This expressed in percentage is 31.92%

4 0

3 years ago

Which of the following is false? the cost to mail an envelope and the weight of the envelope is a positive correlation amount of

inysia [295]

"The amount of exercise and the percent of body fat is a negative correlation" is false.

8 0

4 years ago

A man and a woman agree to meet at a certain location about 12:30 pm. If the man arrives at a time uniformly distributed between

dimaraw [331]

Explanation.

The question is incomplete. However, the complete part of the question simply states that: What is the probability that the man arrives first?

Answer:

Therefore, we can say that the probability that the man will arrive first is half that is 1/2 while the probability that no one will wait more than five times is 1/6

Step-by-step explanation:

We assume the man and the woman arrive at 12:X and 12:Y respectively (1:00 is 12:60). Also, the space of X and Y are [15, 45] and [0, 60] respectively, and fₓ (x) ≡ 1 / (45 − 15) = 1/30, fy (y) ≡ 1 / (60 − 0) = 1 / 60.

So the joint pdf of X and Y is

f(x, y) = 1 / 30 x 1 / 60

= 1 / 1800

where ( x , y ) ∈ [15, 45] × [0, 60].

Consequentially,

P(| X − Y | ≤ 5) = ∫ Iim (45)(15) ∫ lim (x+5)(x-5) f (x,y)dydx

= 1 / 1800 ∫ Iim (45)(15) y | ₓ₋₅ˣ⁺⁵ dx

= 30 x 10 / 1800

300 / 1800

= 1 / 6

Hence,

P( X < Y ) = ∫ Iim (45)(15) ∫ lim (60)(x) f (x,y) dydx

= 1 / 1800 ∫ Iim (45)(15) y | ⁶⁰ₓ dx

= 1 / 1800 ∫ Iim (45)(15) ( 60 - x ) dx

= 60 x − x ²/2 ÷ 1800 ║⁴⁵₁₅

= 1 / 2

8 0

3 years ago

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