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xenn [34]
3 years ago
14

What is the square root of 30

Mathematics
1 answer:
MArishka [77]3 years ago
4 0
5.47722557505 :) have a nice day hope I helped
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What is the formula for distance?
ahrayia [7]

Formula:

Hope this helped, if not, don’t spam.

7 0
3 years ago
A bag contains 99 marbles, some white and some red. The ratio of white marbles to red ones is 5:4. how many white marbles are t
larisa86 [58]

Answer:

55 white

Step-by-step explanation:

So ratio 5:4 is essentially saying, for each 5 white marbles, there are 4 red ones. This can be represented in the equation: 5x+4x=99. We specifically want an integer solution. Because what is 1.2 of a marble? And what is -1 marbles? So as x increases by 1, the entire thing increases by 9. This gives you the equation: 9x=99 which gives you x=11. So there are 55 white and 44 red.

5 0
2 years ago
when returning home Michael and Tessa were able to take the normal route(7.8miles). how far did michael drive on the round trip
BaLLatris [955]

Answer:

15.6 miles

Step-by-step explanation:

5 0
3 years ago
Give the equation of the circle whose center is (5 -3) and goes through (2 5)
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

The standard form for the equation of a circle is

(x-h)^2+(y-k)^2=r^2

From the info given, we have the center, (h, k) as (5, -3) and the x and y coordinates of (2, 5).  We will use these to solve for r-squared, then plug back in what we need to write the equation.

(2-5)^2+(5-(-3))^2=r^2 which simplifies to

(-3)^2+(8)^2=r^2 and

9+64=r^2 so

r^2=73

Filling in the equation:

(x-5)^2+(y+3)^2=73

7 0
3 years ago
The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the​ length, find the
Paul [167]
So.. hmm notice the picture here

we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59

we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2

now.. use the pythagorean theorem
\bf c^2=a^2+b^2\implies \qquad 
\begin{cases}
a=2w+59\\
b=w\\
c=(2w+59)+2\to 2w+61
\end{cases}
\\\\\\
(2w+61)^2=(2w+59)^2+(w)^2
\\  \qquad\qquad \uparrow\qquad \qquad\qquad \qquad \uparrow  \\
\textit{expand using binomial theorem, or FOIL}

you'd end up with a quadratic, after simplifying, solve for "w"

7 0
3 years ago
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