3
2
+
3
−
7
Distribute
(
6
2
−
4
−
5
)
−
1
(
3
2
−
7
+
2
)
(
6
x
2
−
4
x
−
5
)
−
1
(
3
x
2
−
7
x
+
2
)
(6x2−4x−5)−1(3x2−7x+2)
(
6
2
−
4
−
5
)
−
3
2
+
7
−
2
Answer:
1 1/2 or 1.5
Step-by-step explanation:
From the statement of the problem, we know that:
• a train starts at City A and travels 2,158 km to City B,
,
• then it travels 3,793 km from City B to City C.
The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.
Looking at the answer of Clay:
<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>
We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.
Sin θ = opposite leg/hypotenuse
csc θ = hypotenuse /opposite leg =8/7
cot <span>θ = adjacent leg/opposite leg
hypotenuse =8
opposite leg =7
We need to find adjacent leg.
(Opposite leg)² +(adjacent leg)² = hypotenuse²
7² + </span>(adjacent leg)² =8²
(adjacent leg)² = 64 - 49
(adjacent leg)² = 15
adjacent leg=+/-√15
<span>WE need only positive root,
so </span>adjacent leg =√15
cot θ = √15/7 or 0.5533<span>
</span>
Answer:
238 mg
Step-by-step explanation:
340 x 0.30 = 102
340 - 102 = 238