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aalyn [17]
3 years ago
8

Trying to find volume

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:660 in

Step-by-step explanation:10x11x6=660 in

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elijah earned $73 for 6 hours. what was his hourly wage? choose the correct one-step equation to represent this situation.
agasfer [191]

Answer:

73/6= h

His hourly wage was about $12.17

5 0
2 years ago
Help me pls this one is hard
ella [17]

Answer:

2-120

4-240

7-420

Step-by-step explanation:

<em>there are 60 people in each tour group so you multiply 60 by the number of tour groups.</em>

ordered pairs:

<em>(2,120)</em>

<em>(4,240)</em>

<em>(7,420)</em>

hope this helped you!

have a great day!!

7 0
3 years ago
Read 2 more answers
3. A wall is 12 feet high. If its area is 132 sq ft, what is its
dalvyx [7]

B. 46 feet because 132/12=11 and 12+12+11+11=46

5 0
2 years ago
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
2. Describe how to use the conjugate to divide 2 − i by 3 + 2i, and then find the quotient.
DaniilM [7]

Answer:

\frac{4}{13}-\frac{7}{13}i

Step-by-step explanation:

\frac{2-i}{3+2i}

Multiply and divide by the conjugate.

The conjugate is the denominator with the sign of the complex number the opposite of the denominator.

\frac{2-i}{3+2i}\frac{3-2i}{3-2i}\\ =\frac{2\times (3-2i)-i\times (3-2i)}{3^2-(2i)^2}\\ =\frac{6-4i-3i+2i^2}{9+4}\\ =\frac{4-7i}{13}\\ =\frac{4}{13}-\frac{7}{13}i

Quotient = \frac{4}{13}-\frac{7}{13}i

7 0
3 years ago
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