Answer:
b
Step-by-step explanation:
you can use a calculator, or this way of thinking about it :
the sqrt of 49 is 7. so rt46 is too small, and rt51 may be too big. rt50 is closer to rt49 ( 7's square) than rt47. so it is rt50
Answer:
Step-by-step explanation:
The perimeter of a polygon is equal to the sum of its sides.
The sides in the triangle shown have lengths 
, 
, and 
in no specific order.
Since its perimeter is given by the sum of its sides, the perimeter is equal to:
Combine like terms:
Answer: 2 Dogs
Step-by-step explanation: The other dog never left the park
The volume of a cylinder is represented by the following equation...
V=<span><span>πr^2 x </span><span>h
</span></span>
Volume = π(64)(14)
Your volume is 896π
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
