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3 years ago

How much does a customer at David's

Mathematics

1 answer:

alina1380 [7]3 years ago

4 0

Answer:

The solution as an ordered pair is (3,21)

Step-by-step explanation:

The complete question is

At David's skateboard shop, customers pay an upfront fee of $12 and then pay $3 per hour for each hour they use the skateboard.

How much does a customer at David's skateboard shop pay to rent a skateboard for 3 hours?

Write your answer as an ordered pair (h,C)

we know that

The linear equation in slope intercept form is equal to

$C=mh+b$

where

C is the total cost to rent a skateboard

h is the number of hours

m is the slope or unit rate

b is the initial value (the C-intercept)

In this problem we have

The slope is equal to

$m=\$3\ per\ hour$

The C-intercept or initial value is

$b=\$12$

substitute

$C=3h+12$

For h=3 hours

substitute in the linear equation

$C=3(3)+12=\$21$

therefore

The solution as an ordered pair is (3,21)

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sveticcg [70]

Hey there,
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A tangent from point P to a circle of radius 4 cm is 10 cm long. Find: a the distance of P from the centre of the circle <br

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Answer:

see explanation

Step-by-step explanation:

The tangent and the radius at the point of contact form a right angle

Using Pythagoras' identity on the right triangle formed.

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dmitriy555 [2]

Answer:

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5. Choose the fragment which best completes the following sentence. Finance charges on a credit card Include (2 points)

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3 years ago

Let v⃗ 1=⎡⎣⎢033⎤⎦⎥,v⃗ 2=⎡⎣⎢1−10⎤⎦⎥,v⃗ 3=⎡⎣⎢30−3⎤⎦⎥ be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−1, λ2

kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

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x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

Transpose Ax = (12, -6, -6)

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