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crimeas [40]
2 years ago
7

09. Find the rate A sum of money doubled itself in 15 years. In how many years will it become 8 times of itself?​

Mathematics
1 answer:
tamaranim1 [39]2 years ago
5 0

Answer:

45 years

Step-by-step explanation:

Let the sum be x and CI=2x

We know that

CI=P(1+100R)T

2x=x(1+100R) ^15

(1+100R)^15=2                

Let m be the number of years.

Therefore,

x(1+100R)m=8x

(1+100R)m=23

(1+100R)m=[(1+100R)^15]3          

From eqn(1)

(1+100R)m=(1+100R)45

On comparing both power, we get

m=45 years

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Answer:

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Note: Am using the carrot - shift 6 - ^ to denote "to the power of".

Step-by-step explanation:

(x^2 + y)^2 = (x^2 + y) * (x^2 + y)

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In words the answer is: x to the 4th plus 2 yx squared plus y squared.

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