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crimeas [40]
2 years ago
7

09. Find the rate A sum of money doubled itself in 15 years. In how many years will it become 8 times of itself?​

Mathematics
1 answer:
tamaranim1 [39]2 years ago
5 0

Answer:

45 years

Step-by-step explanation:

Let the sum be x and CI=2x

We know that

CI=P(1+100R)T

2x=x(1+100R) ^15

(1+100R)^15=2                

Let m be the number of years.

Therefore,

x(1+100R)m=8x

(1+100R)m=23

(1+100R)m=[(1+100R)^15]3          

From eqn(1)

(1+100R)m=(1+100R)45

On comparing both power, we get

m=45 years

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Vaselesa [24]

Answer:

I think the equation is written as 3r + 2.5p, where r is the number of roses and p is the number of petunias. To find the total cost, substitute 777 to r and 888 to p. The total cost would then be:

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3 0
3 years ago
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ladessa [460]

Answer:

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Hope it helps! :)

8 0
2 years ago
What value of c makes the equation true? −3−3/4(c−4)=5/4 Drag and drop the correct number in the box. c = Response area
gogolik [260]

Answer:

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Step-by-step explanation:

Solve using algebra.

After you do 11 steps, that is the answer.

<h2><u><em>Please mark as Brainliest!!!</em></u></h2>
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3 years ago
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Ket [755]

Answer:

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Step-by-step explanation:

-3x + 8 = y

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Gnoma [55]

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7 0
3 years ago
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