Question

8 people eat at Charlie Brown's for Thanksgiving. How many different seating

Answer 1

Answer: 40,320

Step-by-step explanation: Let's say that there is person A,B,C,D,E,F,G,H. and 8 chairs. For the first chair, 8 different people could potentially sit in it, making 8 different possibilities. No matter who sits there, the logic follows the next table. However, since one person is sitting in the first chair, there are 7 different possibilities about who would be sitting in the second chair. If you multiply the two together, there are 56 different possibilities just for the first and second chair. For the third chair, there are 6 different possibilities about whom could sit. Multiply 56*6 and you get 336 possibilities. Keep multiplying out and you get a grand total of 40,320 different arrangements!

Answer 2

Answer:

5040

Step-by-step explanation:

The answer is (8 - 1)!

The reason is that the first person is fixed. Any place is the same as any other place. After that there are 7! choices for the next position.

Answer: 5040