Does anyone know how to do this?

Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form?

Alenkinab [10]

Y= 3( x -2 )² - ( x-5 )² = 3 ( x² - 4 x + 4 ) - ( x² - 10 x + 25 ) =
= 3 x² - 12 x + 12 - x² + 10 x - 25=
= 2 x² - 2 x - 13 =
= 2 ( x² - x + 1/4 - 1/4 ) - 13 =
= 2 ( x - 1/2 )² - 1/2 - 26/2 = 2 ( x - 1/2 )² - 27/2
Answer: D)

4 0

3 years ago

Draw the angle given in degrees on the unit circle where 0 radians corresponds to the positive portion of the horizontal axis: 2

vivado [14]

Ur answer will c as I Claus

4 0

3 years ago

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Help!1!1!1 ASAP please !1!1

gulaghasi [49]

Answer:

1/4 Teaspoons: 7

1/3 Cup: 20

Step-by-step explanation:

1/3 Cup:

Butter (2), Sugar (4), Coca (3), Flour(11)

1/4 Teaspoon:

Salt (3), Baking Soda (4)

4 0

4 years ago

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Which expression is an equivalent expression of 12x + 10 + 4y?

Klio2033 [76]

You basically multiply the number outside the parentheses by everything inside.
So 2 × 6x = 12x,
2 × 5 = 10,
2 × 2y = 4y.
So your answer is 2(6x + 5 + 2y).

8 0

3 years ago

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Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error