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velikii [3]
3 years ago
9

write an equation to represent the total cost for a certain number of cans. Use "c" for cost and "n" for number of cans​

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

Answer:

C(n)=1.25n

Where n= number of cans

Step-by-step explanation:

C=cost

n=number of cans

Quantity Total cost

1 $1.25

2 $2.50

3 $3.75

4 $5.00

Total cost, c(n) =1.25n

Check

Total cost when n=4

Total cost c(4)=1.25×4

Total cost c(4)=5.00

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What is the value of 6x – 3y if x = 5 and y=-1?<br>F. 11 G. 33 H. 65 1. 65​
atroni [7]

Answer:

it is G.33

brainliest plz

Step-by-step explanation:

7 0
3 years ago
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A bakery has 42 donuts and 24 muffins for sale. What is the ratio of muffins to donuts
Lana71 [14]
The ration is 12 muffins to every 21 donuts
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4x-5=x-1+3x I need help
labwork [276]

Answer:

x = no solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

4x - 5 = x - 1 + 3x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    4x - 5 = 4x - 1
  2. Subtract 4x on both sides:          -5 ≠ -1

Here we see that -5 does not equal -1.

∴ This equation has no solutions.

8 0
2 years ago
He dimensions are tripled. The new surface area would be times larger than the original surface area.
ddd [48]

Answer:

The new surface area would be 9 times larger than the original surface area.

Step-by-step explanation:

Here we do not know what was the original shape, but we will see that it does not matter.

Let's start with a square of side length L.

The original area of this square will be:

A = L^2

Now if each dimension is tripled, then all the sides of the square now will be equal to 3*L

Then the new area of the square is:

A' = (3*L)^2 = (3*L)*(3*L) = 9*L^2 = 9*A

So the new surface area is 9 times the original one.

Now, if the figure was a circle instead of a square?

For a circle of radius R, the area is:

A = pi*R^2

where pi = 3.14

Now if the dimensions of the circle are tripled, the new radius will be 3*R

Then the new area of the circle is:

A' = pi*(3*R)^2 = pi*9*R^2 = 9*(pi*R^2) = 9*A

Again, the new area is 9 times the original one.

If the figure is a triangle?

We know that for a triangle of base B and height H, the area is:

A = B*H/2

If we triple each measure, we will have a base 3*B and a height 3*H

Then the new area is:

A' = (3*B)*(3*H)/2 = (3*3)*(B*H/2) = 9*(B*H/2) = 9*A

Again, the new area is 9 times the original area.

So we can conclude that for any shape, the new area will be 9 times the original area.

3 0
3 years ago
What is the product of 2 2/3 and 2/5
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