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3 years ago

I haven’t really understood this yet

Mathematics

1 answer:

Ad libitum [116K]3 years ago

3 0

Answer:

I believe A, B, and G. sorry if its wrong.

Step-by-step explanation:

The y-intercept, is where the line *intercepts* with the y axis.

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Which line is parallel to the line that passes through the points (1, 7) and (-3, 4)?

Viktor [21]

Answer:

Step-by-step explanation:

The slope of the line that passes through the given points is (4-7)/(-3-1) = 3/4.

Since parallel lines have equivalent slopes, the answer is B.

5 0

2 years ago

Helpppppp<br> Show workings

QveST [7]

Answer:

Step-by-step explanation:

So this one is pretty much like the last one

the distance on the x values is 6 and the distance on the y values is 4

1/6 of 6 is 1 and 1/6 of 4 is .66

We subtract the coordinates from R

4-1 is 3

2 -.66 =1.33

The 1/6 point is at (-3,1.33)

8 0

3 years ago

(6 points) Elderly drivers. A polling agency interviews 748 American adults and finds that 464 think licensed drivers should be

NNADVOKAT [17]

Answer:

1) p-hat = 0.6203

2) std error = 0.0177

3) margin of error = 0.0291

4) (0.5912, 0.6494)

5) minimum sample size = 1683

Step-by-step explanation:

1. The point estimate for the proportion of American adults that think licensed drivers should be required to retake their road test once they reach 65 years of age can be calculating dividing the number of people who answer Yes by the total of people interviewed:

$\hat p=X/N=464/748=0.6203$

2. The standard error of a proportion can be expressed as:

$se_p=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6203*0.3797}{748}}=\sqrt{0.000314877}=0.0177$

3. The z-value for a 90% CI is z=1.64485.

The margin of error can be expressed as:

$me=z\cdot se_p = 1.64485*0.0177=0.0291$

4. The lower and upper limits can be calculated as:

$LL=\hat p - z*se_p=0.6203-0.0291=0.5912\\\\\\UL=\hat p + z*se_p=0.6203+0.0291=0.6494$

5. To have a margin of error of no more than 3.2% of the sample proportion, we have to first calculate what margin of error gives 3.2% of the proportion.

$me=0.032*\hat p=0.032*0.6203=0.0198$

This margin of error can be related to the sample size as:

$me=z*se_p=z*\sqrt{\frac{p(1-p)}{n}} =1.645\sqrt{\frac{0.6203*0.3797}{n}}=0.0198\\\\1.645\sqrt{\frac{0.2355}{n} }=0.0198\\\\ \frac{0.2355}{n} =(0.0198/1.645)^2=0.0120^2=0.00014\\\\n=0.2355/0.00014\\\\n=1682.14\approx1683$