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Luda [366]
2 years ago
15

IMPORTANT, PLEASE HELP QUICKLY! 40 POINTSS

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
7 0

Answer:

\sf 1. \quad \tan(B)=\dfrac{4}{3}

\sf 2. \quad \tan(A)=\dfrac{7}{2}

\sf 3. \quad \angle A

Step-by-step explanation:

<u>Acute angle</u>: an angle less than 90°

<u>Tan trigonometric ratio</u>

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

<u>Question 1</u>

Refer to the first attached diagram.

If tan(A) = 3/4 then the side opposite ∠A is 3 units, and the side adjacent ∠A is 4 units.

Therefore:

\implies \sf \tan(B)=\dfrac{4}{3}

<u>Question 2</u>

Refer to the second attached diagram.

If tan(B) = 2/7 then the side opposite ∠B is ,and the side adjacent ∠B is 7.

Therefore:

\implies \sf \tan(A)=\dfrac{7}{2}

<h3><u>Question 3</u></h3>

Angle A would be bigger (see second attachment).

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