For this case, the first thing we must do is define variables.
x: amount of time Miguel uses to complete the task.
y: amount of time Maria uses to complete the task.
We write the system of equations:
x + y = 60
y = (1/2) x
Solving the system we have:
x = 40 minutes
y = 20 minutes
Answer:
it take her to wash them by herself about:
y = 20 minutes
8.3 : anything multiplied by one is itself
Answer:
Choice C
Step-by-step explanation:
f: initial value of 200 decreasing at a rate of 4%
g: initial value of 40 increasing at a rate of 8%
f is decreasing so it must go down starting at 200
That eliminates a and d
g is increasing and starts at 40 That eliminates a
We must look at b and c
g is increasing faster than f is decreasing
Choice C
Answer:
D
Step-by-step explanation:
(-2 1/2, -3) = (-5/2 , -3) & (1, -3)
![Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(1-[\frac{-5}{2}])^{2}+(-3-[-3])^{2}}\\\\ =\sqrt{(1+\frac{5}{2})^{2}+(-3+3)^{2}}\\\\ =\sqrt{(\frac{7}{2})^{2}} \\\\=\frac{7}{2}\\\\=3\frac{1}{2}](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%281-%5B%5Cfrac%7B-5%7D%7B2%7D%5D%29%5E%7B2%7D%2B%28-3-%5B-3%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%281%2B%5Cfrac%7B5%7D%7B2%7D%29%5E%7B2%7D%2B%28-3%2B3%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28%5Cfrac%7B7%7D%7B2%7D%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B7%7D%7B2%7D%5C%5C%5C%5C%3D3%5Cfrac%7B1%7D%7B2%7D)
The procedure to squaring a two digit number is by multiplying the first number by a integer greater than the number and putting 25 beside it.
Finding the Square of a Value is a simple method. Multiply the specified integer by itself to determine the square number. The square term is always represented as an integer multiplied by two. For example, the square of 5 is 25 multiplied by 5, giving 5×5 = 5² = 25.
What if we want to calculate the square root of a two-digit number . It might be a little challenging. Ordinary multiplication cannot be used to compute the square of two-digit values. This article will show us how to calculate the precise square of such integers.
Simply multiply a single-digit number by itself to find its square. Furthermore, by memorizing the tables from 1 to 10.
We taught about two triangles and how to find the point of any base of a triangle given the other two sides using Pythagoras' theorem.
A right triangle has three sides: the hypotenuse, perpendicular, and base. Pythagoras' theorem states that
Hypotenuse² = Perpendicular² + Base².
to learn more about number visit:
brainly.com/question/17429689
#SPJ4
