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butalik [34]
2 years ago
11

PLEASE HELP URGENTTT

Mathematics
2 answers:
Shtirlitz [24]2 years ago
5 0

Answer:

({2g + 1})^{2}

so,

{4g}^{2}  + 4g + 1

Step-by-step explanation:

extended side: 2g+1

area: w*h

square has same for width and height so squared

Margaret [11]2 years ago
3 0

Answer: g^2+2g+1

Step-by-step explanation: Since she wants each side to be 1 inch larger, each side has a length of g+1. You need to find the area by squaring (g+1).

Write this as (g+1)(g+1). Use the FOIL method to get g^2+g+g+1. Simplify this to g^2+2g+1.

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The system has infinitely many solutions. Rearranging the left side of the 2nd equation and subtracting 3a from both sides gives
Alex_Xolod [135]

Answer:

https://web.williams.edu/Mathematics/sjmiller/public_html/105/hwsolns/HWSolns_Math105_Sp2013.pdf  click the link

Step-by-step explanation:

5 0
2 years ago
Explain why each non-zero integer has two square roots but only one cube root.
lilavasa [31]

if we have a number like say hmm 4, and we say hmmm √4 is ±2, it simply means, that if we multiply that number twice by itself, we get what's inside the root, we get the 4, so (+2)(+2) = 4, and (-2)(-2) = 4, recall that <u>minus times minus = plus</u>.

so, any when we're referring to even roots like \bf \sqrt[2]{~~},\sqrt[4]{~~},\sqrt[6]{~~}...., the positive number, that can multiply itself an even amount of times, will produce a valid value, BUT the negative number that multiply itself an even amount of times, will also produce a valid value.

now, that's is not true for odd roots like \bf \sqrt[3]{~~},\sqrt[5]{~~},\sqrt[7]{~~}...., because the multiplication of the negative number will not produce a valid value, let's put two examples on that.


\bf \sqrt[3]{27}\implies \sqrt[3]{3^3}\implies 3\qquad because\qquad (3)(3)(3)=27&#10;\\\\\\&#10;however\qquad (-3)(-3)(-3)\ne 27~\hspace{8em}(-3)(-3)(-3)=-27&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\sqrt[3]{-125}\implies \sqrt[3]{-5^3}\implies -5\qquad because\qquad (-5)(-5)(-5)=-125&#10;\\\\\\&#10;however\qquad (5)(5)(5)\ne -125~\hspace{10em}(5)(5)(5)=125


so, when the root is an odd root, you will always get only one number that will produce the radicand.

6 0
3 years ago
Tom has a piece of rope that is 105 feet long. He wants to cut the rope into 5 equal pieces. How long will each piece be?
goblinko [34]

Hey there!

\large\boxed{21 ft}

If he is going to cut it into 5 equal pieces then we need to divide 105 by 5.

105 ÷ 5 = 21

So, each piece will be 21 feet long.

Hope this helps!

6 0
3 years ago
A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. T
iragen [17]

Answer:

(5\pi-11.6)ft^2

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

AB=2AD=2(2.9)=5.8\,\,feets

\angle ODA=90^{\circ}

Area of \Delta AOB = 1/2 (base) × (height) = \frac{1}{2}\times 4\times 5.8=11.6  square feets

Area of sector AOBC = \frac{\angle AOB}{360^{\circ}}\pi(r^2)=\frac{72^{\circ}}{360^{\circ}}\pi(5^2)=5\pi  square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of \Delta AOB = (5\pi-11.6)ft^2  

Download pptx
3 0
3 years ago
Find x. Round your answer to the nearest tenth of a degree.
Nonamiya [84]

Answer:

42°

Step-by-step explanation:

8 is the opposite

12 is the hypotenuse

We know from SOHCAHTOA to use sine

Since we are looking for the angle, we use sin^-1

sin^-1(opposite/hypotenuse)=x

sin^-1(8/12)=x

Input into calculator

x=42°

7 0
2 years ago
Read 2 more answers
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