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mariarad [96]
3 years ago
7

Find the sum. 5 2a a? + 2a + 1 + a2 + 4a + 3

Mathematics
2 answers:
Vinvika [58]3 years ago
7 0

Answer:

=  \frac{2 {a}^{2}  + 11a + 5}{  {(a + 1)}^{2}(a + 3)} \\

Step-by-step explanation:

\frac{2a}{ {a}^{2}  + 2a + 1} +  \frac{5}{ {a}^{2} + 4a + 3 } \\  \frac{2a}{(a + 1)(a + 1)}    +  \frac{5}{(a + 1)(a + 3)}  \\   \frac{2a}{ {(a + 1)}^{2} }  +  \frac{5}{(a + 1)(a + 3)}  \\  \frac{2a(a + 3) + 5(a + 1)}{ {(a + 1)}^{2}(a + 3) }  \\  \frac{2 {a}^{2} + 6a + 5a + 5 }{ {(a + 1)}^{2}(a + 3)} \\  =  \frac{2 {a}^{2}  + 11a + 5}{  {(a + 1)}^{2}(a + 3)}

Salsk061 [2.6K]3 years ago
5 0

\frac{2a}{a^2+2a+1}+\frac{5}{a^2+4a+3}

Factor the denominators.

\frac{2a}{\left(a+1\right)^2}+\frac{5}{\left(a+1\right)\left(a+3\right)}

Adjust fractions based on LCM.

\frac{2a\left(a+3\right)}{\left(a+1\right)^2\left(a+3\right)}+\frac{5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}

Denominators are same, so add the fractions.

\frac{2a\left(a+3\right)+5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}

Expand the numerator.

\frac{2a^2+11a+5}{\left(a+1\right)^2\left(a+3\right)}

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78

Step-by-step explanation:

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Ricardo Gutierrez has a box of coins that he uses when playing poker with friends. The box currently contains 46 coins, consisit
Nonamiya [84]
Let x be the number of pennies which is also equal to the number of dimes. By this representation, the number of quarters is equal 46 - 2x. The total amount is $4.87 or 487 cents. The equation that best represent the given is,
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The value of x from the equation is 17. Therefore, there are 17 of both pennies and dimes and 12 quarters. 
8 0
3 years ago
Renee was able to plant 15 plant in 5min at this rate how many flowers could she paint plant in 45 min
Sedbober [7]

Answer:

Answer is 135 plant

Step-by-step explanation:

We have given that,

In 5 min Renee can plant 15 plant.

That means in one minute Renee can plant \frac{15}{5} plant.

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So, In 45 minutes , she can plant  45×3 plant

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6 0
3 years ago
What is the solution of the system? y=2 x= -1
kodGreya [7K]

Answer:

( -1,2)

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A company finds that if they price their product at $ 35, they can sell 225 items of it. For every dollar increase in the price,
Basile [38]

Answer:

Maximum revenue = $8000

The price that will guarantee the maximum revenue is $40

Step-by-step explanation:

Given that:

Price of product = $35

Total sale of items = 225

For every dollar increase in the price, the number of items sold will decrease by 5.

The total cost of item sold = 225 ×35

The total cost of item sold = 7875

If c should be the dollar unit in price increment;

Therefore; the cost function is : [35+c(1)][225-5(c)]

For maximum revenue;

\dfrac{d}{dc}(cost \ function) =0

\dfrac{d}{dc}[[35+c(1)][225-5(c)]]=0

0+225-35× 5 -10c = 0

225 - 175  =10c

50 = 10c

c = 50/10

c = 5

Maximum revenue = [35+c(1)][225-5(c)]

Maximum revenue = [35+5(1)][225-5(5)]

Maximum revenue = (35 + 5)(225-25)

Maximum revenue = (40 )(200)

Maximum revenue = $8000

The price that will guarantee the maximum revenue is :

=(35 +c)

= 35 + 5

= $40

8 0
3 years ago
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