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Rom4ik [11]
3 years ago
14

Your company has just taken out a 1-year installment loan for $72,500 at a nominal rate of 20.0% but with equal end-of-month pay

ments. What percentage of the 2nd monthly payment will go toward the repayment of principal?
Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer:

100% of the 2nd monthly payment go toward the repayment of principal.

Step-by-step explanation:

The loan taken is the Principal which is mentioned as $72,500 with interest at a nominal rate of 20%. Firstly, it is important to understand that nominal rate means <em>non-compounding </em>rate. Simply put will be a "<em>one-time charged" </em>rate on the loan. Since this is given as 20% of the Principal. It is calculated thus: \frac{20}{100} × \frac{72,500}{1}= $14,500. So the interest on the loan is $14,500. Added to the Principal the total amount to be paid back by the company becomes: $72,500 + $14,500 = $87,000. To pay back this amount at equal end-of-month installments in 1 year (12 months), we divide the total amount by 12. i.e \frac{87000}{12} = $7250. This means, the monthly payment will be $7,250. Since the monthly payment pays only 10% of the initial principal $72,500. By the second month only 20% of the Principal would have been paid. So all of the monthly payment will go towards repaying the principal

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PLEASE HELP VERY URGENT
worty [1.4K]

Answer:

A. square root of a^2 + b^2 for both answers

Step-by-step explanation:

The first problem, we are given

a^2 + b^2 = c^2

What we do is solve for c.

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

For problem 2,

WE can apply the Pythagorean theorem because we have a right triangle.

The equations is

a^2 + b^2 = c^2 like the first problem

Solving gets us

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

3 0
2 years ago
The quotient of j and 8 expressed
Oksana_A [137]
j:8=\dfrac{j}{8}
8 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 14% of scores B: Scores below the
NeX [460]

Answer:

Grades between 62 and 64 result in a D grade.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 71.9, \sigma = 7.8

Find the numerical limits for a D grade.

D: Scores below the top 84% and above the bottom 10%

So below the 100-84 = 16th percentile and above the 10th percentile.

16th percentile:

This is the value of X when Z has a pvalue of 0.16. So X when Z = -0.995.

Z = \frac{X - \mu}{\sigma}

-0.995 = \frac{X - 71.9}{7.8}

X - 71.9 = -0.995*7.8

X = 64

10th percentile:

This is the value of X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 71.9}{7.8}

X - 71.9 = -1.28*7.8

X = 62

Grades between 62 and 64 result in a D grade.

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What is 25% as a fraction.
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