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3 years ago

What is 8.85 round to the nearest tenth

2 answers:

7 0

The tenths place is directly after the decimal. Here, it is eight. To determine whether you should round up (to 9) or down (stay at 8), look to the number to the right of the tenths place. If it greater than or equal to 5, you should round up. If it less than 5, round down. 5 is equal to 5 so you should round up.

8.85 rounded to the nearest tenth is 8.9.

Hope this helps!!

VikaD [51]3 years ago

4 0

Answer:

8.9

Step-by-step explanation:

The rules for rounding are if the number is 5 or higher, round up. If it is 4 or lower, round down.

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How many solutions does the system have? y = x + 1 y = 2x - 5 Please Help

olga55 [171]

Answer:

One solution: x=6, y=7. (6, 7).

Step-by-step explanation:

y=x+1

y=2x-5

-----------

x+1=2x-5

1=2x-x-5

x-5=1

x=1+5

x=6

y=6+1=7

8 0

3 years ago

Find the particular solution of the differential equation? /=5^3+9^2, when =1, =8

kipiarov [429]

Answer:

$\displaystyle s = \frac{5t^4}{4} + \frac{9}{t} - \frac{9}{4}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Solving Differentials - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Step-by-step explanation:

*Note:

Ignore the Integration Constant C on the left hand side of the differential equation when integrating.

Step 1: Define

$\displaystyle \frac{ds}{dt} = 5t^3 + \frac{9}{t^2}$

t = 1

s = 8

Step 2: Integrate

[Derivative] Rewrite [Leibniz's Notation]: $\displaystyle ds = (5t^3 + \frac{9}{t^2})dt$
[Equality Property] Integrate both sides: $\displaystyle \int {} \, ds = \int {(5t^3 + \frac{9}{t^2})} \, dt$
[Left Integral] Reverse Power Rule: $\displaystyle s = \int {(5t^3 + \frac{9}{t^2})} \, dt$
[Right Integral] Rewrite [Integration Property - Addition]: $\displaystyle s = \int {5t^3} \, dt + \int {\frac{9}{t^2}} \, dt$
[Right Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle s = 5\int {t^3} \, dt + 9\int {\frac{1}{t^2}} \, dt$
[Right Integrals] Rewrite [Exponential Rule - Rewrite]: $\displaystyle s = 5\int {t^3} \, dt + 9\int {t^{-2}} \, dt$
[Right Integrals] Reverse Power Rule: $\displaystyle s = 5(\frac{t^4}{4}) + 9(\frac{t^{-1}}{-1}) + C$
[Right Integrals] Rewrite [Exponential Rule - Rewrite]: $\displaystyle s = 5(\frac{t^4}{4}) + 9(\frac{1}{t}) + C$
Multiply: $\displaystyle s = \frac{5t^4}{4} + \frac{9}{t} + C$

Step 3: Solve

Substitute in variables: $\displaystyle 8 = \frac{5(1)^4}{4} + \frac{9}{1} + C$
Evaluate exponents: $\displaystyle 8 = \frac{5}{4} + \frac{9}{1} + C$
Divide: $\displaystyle 8 = \frac{5}{4} + 9 + C$
Add: $\displaystyle 8 = \frac{41}{4} + C$
[Subtraction Property of Equality] Isolate C: $\displaystyle \frac{-9}{4} = C$
Rewrite: $\displaystyle C = \frac{-9}{4}$

Particular Solution: $\displaystyle s = \frac{5t^4}{4} + \frac{9}{t} - \frac{9}{4}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Differentials Equations and Slope Fields

Book: College Calculus 10e

3 0

3 years ago

Find the sum of 2x 2 + 3x - 4, 8 - 3x, and -5x 2 + 2.

azamat

First one is 5x-2 Second one is 8-3x and Third is -5x*4

3 0

3 years ago

8 - 3(k + 2) = 2-3k

Rus_ich [418]

Answer:

Any value of k makes the equation true.

All real numbers

Interval Notation:

( − ∞ , ∞ )

5 0

3 years ago

Derek’s bike has a mass of 12 kg and he is riding at a velocity of 8 m/s. What is the kinetic energy of the bike

Marrrta [24]

Answer: The kinetic energy of Derek's bike is 384.

To find the kinetic energy of an object, we need to know the mass and the velocity of the object. Both of those are already given in the problem. So we can simply use the formula.

The formula for kinetic energy is KE =0.5(m)v^2. All we need to do is input the know variables and evaluate.

KE = 0.5 (12) (8^2)
KE = 0.5(12)(64)
KE = 384

4 0

4 years ago