All categories

3 years ago

Eurostar is a high-speed railway service connecting

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).

350000 passengers

(350000 passengers) * 1

(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)

[note: passengers and carriages cancel. Leaving only trains]

(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]

729.1667 trains [oh, but don’t just round this number either up or down]

729 full trains can carry 729*32*15 = 349920 passengers

730 full trains can carry 730*32*15 = 350400 passengers

Now, we can say that 730 trains are adequate to carry 350000 passengers.

You might be interested in

Please answer this correctly

Nitella [24]

Answer:

=3651 km^2

Step-by-step explanation:

The rectangle at the top is 11 km by 32 km

The area is 11*32 =352

The rectangle at the bottom is 9 km by 11 km

The area is 9*11 = 99

Add the two areas together

352+99 =451 km^2

6 0

3 years ago

Tyina is buying 12 shirts for the drama club. She will

Stolb23 [73]

Answer: if you times 12x2.75 I got 33 some she can spend $33.00 and not go over.

3 0

4 years ago

Thanks!! got a 100% on the test bc of brain.ly

Lorico [155]

Your welcome ig brainly helps everyone in need of help

5 0

4 years ago

Read 2 more answers

Use the following steps to prove that log b(xy)- log bx+ log by.

borishaifa [10]

Answer with Step-by-step explanation:

a. $x=b^p$

$y=b^q$

Taking both sides log

$log x=plog b$

Using identity: $logx^y=ylogx$

$p=\frac{logx}{log b}=log_b x$

Using identity: $log_x y=\frac{log y}{log x}$

$log y=qlog b$

$q=\frac{log y}{log b}=log_b y$

b. $xy=b^pb^q$

We know that

$x^a\cdot x^b=x^{a+b}$

Using identity

$xy=b^{p+q}$

c. $log_b(xy)=log_b(b^{p+q})$

$log_b(xy)=(p+q)log_b b$

Substitute the values then we get

$log_b(xy)=(log_b x+log_b y)$

By using $log_b b=1$

Hence, $log_b(xy)=log_b x+log_b y$

3 0

3 years ago

Determine if events A and B are mutually exclusive.

gladu [14]

Answer:

A) Not mutually exclusive

Step-by-step explanation:

Given

$P(A) = \frac{1}{4}$

$P(B) = \frac{3}{5}$

$P(A\ or\ B) = \frac{7}{10}$

Required

Determine if they are mutually exclusive or not

Mutually exclusive are defined by:

$P(A\ or\ B) = P(A) + P(B)$

So, we have:

$P(A\ or\ B) = \frac{1}{4} + \frac{3}{5}$

Take LCM

$P(A\ or\ B) = \frac{5+12}{20}$

$P(A\ or\ B) = \frac{17}{20}$

By comparing:

$P(A\ or\ B) = \frac{17}{20}$ ---- Calculated

$P(A\ or\ B) = \frac{7}{10}$ ---- Given

We can conclude that A and B are not mutually exclusive because:

$\frac{17}{20} \ne \frac{7}{10}$

6 0

3 years ago