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DerKrebs [107]
3 years ago
15

3(9y+5x)+2(7y+8x)+6 HELPP

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

31x+41y+6

Step-by-step explanation:

Distribute

27y+15x+14y+16x+6

Combine like terms

41y+31x+6

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What is the simplified form of √ 2160x^8/60x^2
s344n2d4d5 [400]
2160 x^8       36 x^6
------------ = 
60 x^2
7 0
3 years ago
Read 2 more answers
1. Moesha needs $79 for a class trip. 59
Whitepunk [10]

Answer: 79=8h +22

Step-by-step explanation: 79 total needed 8h equals 8 times her hourly earning plus 22 what she already haves should equal 79.

8 0
4 years ago
Which binomial is a factor of x^2 + 2x - 15
Shalnov [3]

Answer:

(x−5)(x+3)

Step-by-step explanation:

To factorise, we firstly need two brackets, each containing an x.

(x)(x)

This creates the x2 term.

Now we need to get the rest of the terms. To do this, we need two factors of −15 which will add/subtract to give us +2

The two factors that do this are −3 and 5, as −3+5=2

∴(x−3)(x+5)

You can check by expanding it out.

8 0
3 years ago
Item 3 What is the length of the base of a right triangle with an area of 15 m² and a height of 3 m? 5 m 10 m 30 m 45 m
Ksivusya [100]

Answer:

10m

Step-by-step explanation:

Use the area of triangle:

Area of triangle =

\frac{1}{2}   \times base \:  \times height

1/2 × b × 3 = 15

b × 3 = 30

b = 30/3

b = 10

3 0
3 years ago
f 20% of the population are homozygous for the scalp-wiggling allele •(qq, or q 2), then what proportion of the population is ho
11Alexandr11 [23.1K]

Answer:

The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

Step-by-step explanation:

Denote the variables as follows:

<em>q²</em> = number of people who are homozygous for the scalp-wiggling allele.

<em>p²</em> = number of people who are homozygous for the non-wiggling allele.

It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, <em>q²</em> = 0.20.

Compute the value of <em>q</em> as follows:

q^{2}=0.20\\q=\sqrt{0.20}\\=0.4472

Compute the value of <em>p</em> as follows:

p=1-q\\=1-0.4472\\=0.5528

Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:

p^{2}=(0.5528)^{2}=0.30558784\approx0.3056

Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

7 0
3 years ago
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