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NARA [144]
3 years ago
8

And please show work (answer #4)

Mathematics
1 answer:
algol [13]3 years ago
8 0
Part A.

The building is made up of two rectangular prism.
The left rectangular prism has base 8 ft by 12 ft and height 24 ft.
The right rectangular prism has base 32 ft by 12 ft and height 16 ft.
The volume of a rectangular prism is: V = LWH

For the building, the total volume is:

V = LWH + LWH

V = 8 ft * 12 ft * 24 ft + 32 ft * 12 ft * 16 ft

Part B.

V = 2304 ft^3 + 6144 ft^3

V = 8448 ft^3
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If the length of a rectangle is 5 m more than its width find the values of length and width if the area of a rectangle is 500 m²
astra-53 [7]

Answer:

Length of the rectangle  =25

width of the rectangle  = 20

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'x' be the width of the rectangle

Given that the length of a rectangle is 5 m more than its width

Given that Area of the rectangle = 500m²

length of a rectangle = x +5

width of a rectangle = x

<u><em>Step(ii):-</em></u>

Area of the rectangle = length × width

             500 = x ( x+5)

          x² + 5 x = 500

      ⇒  x² + 5 x - 500 =0

      ⇒  x² +25x - 20 x - 500 =0

    ⇒  x( x+25) -20(x+25) =0

  ⇒  (x-20)(x+25) =0

 ⇒  x =20 and x=-25

we can choose x =20

<u><em>Step(iii):-</em></u>

Length of the rectangle = x +5 = 20 +5 =25

width of the rectangle  = 20

<u><em>Final answer</em></u>:-

Length of the rectangle  =25

width of the rectangle  = 20

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