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Anvisha [2.4K]
3 years ago
6

What is the volume of an oblique square pyramid with base edges 25 ft and height 24 ft?

Mathematics
2 answers:
Oliga [24]3 years ago
3 0
24 and 25 divide will give you the final answer
GaryK [48]3 years ago
3 0

Answer:

15000\text{ ft}^3

Step-by-step explanation:

We are asked to find the volume of an oblique square pyramid with base edges 25 ft and height 24 ft.

We know that area of an oblique prism equals to the product of base area and height of prism.

\text{Volume of oblique prism}=\text{Base area* Height}

Since base of prism is square, so area of base would be: (25\text{ ft})^2=625\text{ ft}^2.

\text{Volume of oblique prism}=625\text{ ft}^2\times 24\text{ ft}

\text{Volume of oblique prism}=15000\text{ ft}^3

Therefore, the volume of our given oblique prism would be 15000\text{ ft}^3.

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Answer:

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In the following picture, (QS) ̅ and (PR) ̅ are chords of the circle. Find the length of QS. (Remember to show formulas/equation
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<h3>Answer: QS is 37 units long</h3>

=========================================

Explanation:

PN = 24 and NR = 14 are pieces of the chord PR. The two pieces multiply to some value. At the same time, the other two pieces QN = 21 and NS = 2x-4 also multiply to that same value. In short, the chord pieces multiply to the same number. This is known as the intersecting chord theorem.

PN*NR = QN*NS

24*14 = 21*(2x-4)

336 = 42x-84

336+84 = 42x-84+84 .... add 84 to both sides

420 = 42x

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42x/42 = 420/42 ...... divide both sides by 42

x = 10

We know that x = 10 so we can use it to find the length of NS

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NS = 2*10-4

NS = 20-4

NS = 16

Therefore,

QS = QN + NS

QS = 21 + 16

QS = 37

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note: as a check,

PN*NR = QN*NS

24*14 = 21*16

336 = 336

we get a true equation, so we have the proper values

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3 years ago
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