In △ABC, m∠A = α, m∠B = β, m∠C = γ. AB = c, AC = b, BC = a. Find the areas of the triangles if the following parts are given.
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
A = c/sin C, and b by the proportion b/sin B = c/sin C.
a/sin 37° = 4380/sin 109°
a sin 109° = 4380 sin 37°
a = 4380 sin 37°/sin 109° ≈ 2787.8
b/sin 34° = 4380/sin 109°
b sin 109° = 4380 sin 34°
b = 4380 sin 34°/sin 109° ≈ 2590.4
                                
             
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