12 - t|3r - 2|
r = -6; t = 3
subtitute:
12 - 3 · |3 · (-6) - 2| = 12 - 3 · |-18 - 2| = 12 - 3 · |-20| = 12 - 3 · 20 = 12 - 60 = -48
Given:
There are given the edge of the cube-shaped aquarium has 3 feet.
Explanation:
To find the value, we need to use the volume of the cube formula:
So,
From the formula of volume:

Where
a represents the value of edge.
So,
Put the value of edge into the above formula:
Then,

Now,
The water has a density of 62 pounds per cube foot.
According to the question:
If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

Final answer:
Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.
And,
No, the density of water would not change.
The graph that matches the following system of equation is; the picture of a coordinate plane with line y equals negative 4x minus 1 and line y equals minus 3 over 2 times x plus 4. They intersect at negative 2, 7.
<h3>What is the graph of a function?</h3>
The graph of a function y = f(x) shows the position of the x-intercepts and y-intercepts from the graph from which the slope can be drawn.
The system of linear equations can be rewritten in slope-intercept form as follows:
y = -4x - 1
y = -3/2x + 4
From the graph, the two equations intercept at point (-2,7).
Learn more about plotting the graph of a function here:
brainly.com/question/3939432
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P'(-3,-8) Q'(-6,4) R'(1,-1)
This should be correct! Hope I helped!
<span>points (6,10)
</span>y = -x
x + y = 0
distance = lax1 + by1 + cl/√(a^2 + b^2)
= l1(6) + 1(10) + 0l/√(1^2 + 1^2)
= l6 + 10 + 0l/√(1 + 1)
= l16l/√2
= 16/√2
= 8 .2/√2
= 8 . √2.√2/√2
= 8√2