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liraira [26]
3 years ago
10

Using the Histogram below, how many trees are between 150 cm and 200 cm tall?

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

I am pretty sure the answer is 30 trees, if I am not mistaken. (I took the test and forgot the answer but pretty sure its 30)

Step-by-step explanation:

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The function f(x) varies inversely with x and f(x)=0.5 when x = 0.3. What is f(x) when x = 2.4? A)5.76 B)0.0625 C)0.30 D)0.15
goldfiish [28.3K]

Answer:

B) 0.0625

Step-by-step explanation:

f(x) = k / x

f(x)=0.5 when x = 0.3

f(x) = k / x

0.5 = k / 0.3

Cross product

0.5 * 0.3 = k

k = 0.15

What is f(x) when x = 2.4?

f(x) = k / x

f(x) = 0.15 / 2.4

f(x) = 0.0625

The answer is B) 0.0625

3 0
3 years ago
Which statement is supported by the histograms? The two data sets have the same distribution and same range. The two data sets h
Ad libitum [116K]

Answer:

The two data sets have different distributions and different ranges.

Step-by-step explanation:

When you subtract for both of the ranges they are different numbers. So that's the second part. The numbers along the bottom are different too so that is the different distributions.

5 0
3 years ago
What is 17% of 13.00
Margarita [4]

Answer:

The answer is 2.21

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
For his birthday, Tyrone's parents gave him $7,790.00 which they put into a savings account that earns 15% interest compounded m
torisob [31]

Answer:

5 years and 5 months

Step-by-step explanation:

<u />

<u>Compound Interest Formula</u>

\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • A = $17,474.00
  • P = $7,790.00
  • r = 15% = 0.15
  • n = 12
  • t = number of years

Substitute the given values into the formula and solve for t:

\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}

\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)

\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}

\implies \sf t=5.419413037...\:years

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

3 0
2 years ago
Read 2 more answers
First-person to answer correctly with an explanation get brainiest.
Aneli [31]

Answer:

x = 8

Step-by-step explanation:

I think this is the answer if I am wrong please do not report me

I hope this helps! :}

4 0
3 years ago
Read 2 more answers
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